Solution guide for exercise 1 on pages 145-146 Math 5 textbook
a) Calculate the distance covered by the motorcycle approaching the bicycle each hour by subtracting the cyclist's speed from the motorcyclist's speed. Then calculate the time taken for the motorcycle to catch up with the bicycle by dividing the distance from point A to point B by the distance covered by the motorcycle approaching the bicycle each hour. b) Calculate the distance covered by the bicycle ahead of the motorcycle by multiplying the cyclist's speed by the time taken for the motorcycle to travel from point A to point B. Then calculate the distance covered by the bicycle after each hour the motorcycle approaches by subtracting the distance covered by the bicycle ahead of the motorcycle from the cyclist's speed. Finally, calculate the time for the motorcycle to catch up with the bicycle by dividing the distance covered by the bicycle ahead of the motorcycle by the distance covered by the bicycle after each hour the motorcycle approaches.
Answer:
a) Motorcycle approaches bicycle every hour:
36 - 12 = 24 (km).
Time taken for motorcycle to catch up with bicycle:
48 : 24 = 2 (hours).
Answer:
b) Distance bicycle travels ahead of motorcycle:
12 x 3 = 36 (km).
Motorcycle approaches bicycle every hour:
36 - 12 = 24 (km).
Time for motorcycle to catch up with bicycle:
36 : 24 = 1.5 (hours)
Conversion: 1.5 hours = 1 hour 30 minutes.
Final answer: 1 hour 30 minutes.
Here's the solution guide for exercise 1 on pages 145-146 of Math 5 textbook in the concentrated practice section. Additionally, there are 2 other exercises in this section: Solving exercise 2 on pages 145-146 of Math 5 textbook and Solving exercise 3 on pages 145-146 of Math 5 textbook. Let's check out the Solution for Math class 5 pages 145-146 to excel in Math class 5.
