Grade 4 math exercises on page 98 practice, answers for exercises 1, 2, 3, 4 Textbook

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Guide to solving grade 4 math exercises on page 98 Practice (including solving methods)

1. Grade 4 Exercise on Page 98 Practice 1

Problem:
Among the numbers 3451; 4563; 2050; 2229; 3576; 66816.
a) Which numbers are divisible by 3?
b) Which numbers are divisible by 9?
c) Which numbers are divisible by 3 but not by 9?

Solution Method:
- Divisible by 3 criterion: If the sum of the digits is divisible by 3, then the number is divisible by 3
- Divisible by 9 criterion: If the sum of the digits is divisible by 9, then the number is divisible by 9.

Answer:
Number 3451 has a sum of digits equal to 3 + 4 + 5 + 1 = 13;
Number 4563 has a sum of digits equal to 4 + 5 + 6 + 3 = 18;
Number 2050 has a sum of digits equal to 2 + 0 + 5 + 0 = 7;
Number 2229 has a sum of digits equal to 2 + 2 + 2 + 9 = 15;
Number 3576 has a sum of digits equal to 3 + 5 + 7 + 6 = 21;
Number 66816 has a sum of digits equal to 6 + 6 + 8 + 1 + 6 = 27.
Therefore:
a) Numbers divisible by 3 are: 4563; 2229; 3576; 66816.
b) Numbers divisible by 9 are: 4563; 66816.
c) Numbers divisible by 3 but not by 9 are: 2229; 3576.

2. Grade 4 Math Exercise on Page 98 Practice 2

Solution Method:
- Divisible by 3 criterion: The sum of the digits must be divisible by 3 for the number to be divisible by 3
- Divisible by 9 criterion: The sum of the digits must be divisible by 9 for the number to be divisible by 9
- A number divisible by both 3 and 2 must have a sum of digits divisible by 3 and end with 0, 2, 4, 6, or 8.

3. Grade 4 Math Exercise on Page 98 Practice 3

Problem:
Which statement is correct, which one is incorrect?
a) Number 13 465 is not divisible by 3;
b) Number 70 009 is divisible by 9;
c) Number 78 435 is not divisible by 9;
d) A number ending with 0 is divisible by 2 and 5.

Solution Method:
- Divisible by 3 criterion: The sum of the digits must be divisible by 3 for the number to be divisible by 3
- Divisible by 9 criterion: The sum of the digits must be divisible by 9 for the number to be divisible by 9
- A number divisible by both 5 and 2 must have a digit ending with 0.

c) Incorrect

Problem:
For the 4 digits 0; 6; 1; 2.
a) Write at least three numbers with three digits (three different digits) divisible by 9.
b) Write one number with three digits (three different digits) divisible by 3 but not divisible by 9

Solution Method:
- Divisible by 3 criterion: If the sum of the digits is divisible by 3, then the number is divisible by 3
- Divisible by 9 criterion: If the sum of the digits is divisible by 9, then the number is divisible by 9

Answer:
a) You can choose 3 numbers from the following numbers: 612; 621; 162; 126; 261; 216.
b) You can choose one of the following numbers: 102; 120; 201; 210

Concise Guide to Grade 4 Math Exercise on Page 98 Practice

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Here concludes the Grade 4 Math Exercise solutions for page 98 in the textbook. Students may review the previously solved Grade 4 Math Exercise on page 97 or preview the Grade 4 Math Exercise on page 99 to enhance their understanding of Grade 4 Math.