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Exercises 1, 2, 3, 4 in Math exercise book for Grade 4 pages 108, 109 all have detailed solutions in the document Grade 4 Math Solutions pages 108, 109 VBT Volume 2, Review on finding two numbers when given their sum and difference, exercise 170. Students can refer to this for comparison and reinforcement of the lesson.
Grade 4 math exercises on pages 108, 109 VBT Volume 2, Review on finding two numbers when given their sum and difference, exercise 170
1. Solve Exercise 1 - Math exercise book for Grade 4 page 108
Problem Statement:
Find x and y then fill in the blank cells:
Solution Method:
Find x and y using the formula for finding two numbers when given their sum and difference:
The larger number = (Sum + Difference) :2;
The smaller number = (Sum − Difference) :2
(where x is the larger number, y is the smaller number, x+y is the sum, and x−y is the difference).
Answer
2. Solve Exercise 2 - Math exercise book for Grade 4 page 108
Problem Statement:
A school has 1025 students, with 147 fewer female students than male students. Calculate the number of male and female students in the school.
Solution Method:
Apply the formula:
The larger number = (Sum + Difference) :2;
The smaller number = (Sum − Difference) :2
Answer
The number of female students in the school is:
(1025 - 147) : 2 = 439 (students)
The number of male students in the school is:
439 + 147 = 586 (students)
Answer: Boys: 586 students; Girls: 439 students.
3. Solve Exercise 3 - Math exercise book for Grade 4 page 109
Problem Statement:
The average of two numbers is 262. The first number exceeds the second by 226. Find the two numbers?
Solution Method:
- Find the sum of the two numbers = average x 2.
- Find the two numbers using the formula for finding two numbers when given their sum and difference:
The larger number = (Sum + Difference) :2;
The smaller number = (Sum − Difference) :2
Answer
The sum of the two numbers is:
262 x 2 = 524
We have the diagram:
The first number is:
(524 + 226) : 2 = 375
The second number is:
375 - 226 = 149
Answer: First number : 375 ; Second number : 149.
4. Solve Exercise 4 - Math exercise book for Grade 4 page 109
Problem Statement:
The average of two numbers is 1000. If the second number decreases by 468 units, it becomes the first number. Find the two numbers?
Solution Method:
- Find the sum of the two numbers = average x 2
- Since the second number decreases by 468 units to become the first number, the difference between the second number and the first number is 468 units.
- Find the two numbers using the formula for finding two numbers when given their sum and difference:
The larger number = (Sum + Difference) :2;
The smaller number = (Sum − Difference) :2
Answer
The sum of those two numbers is:
1000 x 2 = 2000
Since the second number decreases by 468 units to become the first number, the difference between the second number and the first number is 468 units (or the second number is 468 units greater than the first number).
We have the diagram:
The first number is:
(2000 - 468) : 2 = 766
The second number is:
766 + 468 = 1234
Answer: First number: 766 ; Second number: 1234.
You are currently viewing the guide for solving Math problems for Grade 4 on pages 108, 109 of VBT Volume 2. This section revises finding two numbers given their sum and difference in exercise 170. You may review the guide Solving Math for Grade 4 on pages 106, 107 of VBT Volume 2 to practice finding the average, or preview the guide Solving Math for Grade 4 on pages 110, 111 of VBT Volume 2 to practice finding two numbers given their sum, difference, and ratio of the two numbers for better understanding of the lesson.
