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Solve Grade 5 Math Problems on Pages 24, 25, 26 of VBT Workbook Volume 2, Practice Exercise 106. Detailed solutions for exercises 1, 2, 3, 4, 5 according to the curriculum. Students can use this to complete assignments easily or cross-check their work. This will help them understand concepts, apply formulas for lateral surface area, total surface area of rectangular prisms in related problem types.
Grade 5 Math Problems Solution - Workbook Volume 2, Practice Exercise 106
1. Solve Exercise 1 - Grade 5 Math Workbook Exercise 2 Page 24
Problem:
Complete the following: A rectangular prism has a length of 20dm, a width of 1.5m, and a height of 12dm.
a. The lateral surface area of the rectangular prism is ........................
b. The total surface area of the rectangular prism is .....................
Solution Method
- To find the lateral surface area of the rectangular prism, multiply the perimeter of the base by the height (using the same unit of measurement).
- To find the total surface area of the rectangular prism, add the lateral surface area to the area of the two bases.
Answer
Convert: 20dm = 2m ;
12dm = 1.2m.
The perimeter of the base of the rectangular prism is:
(2 + 1.5) x 2 = 7 (m)
The lateral surface area of the rectangular prism is:
7 x 1.2 = 8.4 (m2)
The area of the base of the rectangular prism is:
2 x 1.5 = 3 (m2)
The total surface area of the rectangular prism is:
8.4 + 3 x 2 = 14.4 (m2)
So we have the following result:
a) The lateral surface area of the rectangular prism is 8.4m2.
b) The total surface area of the rectangular prism is 14.4m2.
2. Solve problem 2 - Math workbook grade 5 volume 2 page 25
Problem:
Calculate the lateral surface area and total surface area of the rectangular prism with a length of 3/5 m, a width of 1/4 m, and a height of 1/3 m.
Solution Method
- To calculate the lateral surface area of the rectangular prism, multiply the perimeter of the base by the height (using the same unit of measurement).
- To calculate the total surface area of the rectangular prism, add the lateral surface area to the area of the two bases.
Answer
Perimeter of the base of the rectangular prism is:
(3/5 + 1/4) x 2 = 17/10 (m)
Lateral surface area of the rectangular prism is:
17/10 x 1/3 = 17/30 (m2)
Area of the base of the rectangular prism is:
3/5 x 1/4 = 3/20 (m2)
Total surface area of the rectangular prism is:
17/30 + 2 x 3/20 = 13/15 (m2)
Answer: 17/30 m2; 13/15 m2
3. Solve problem 3 - Math workbook grade 5 volume 2 page 25
Problem:
Circle the letter before the correct answer :
The lateral surface area of a rectangular box with a length of 1.1m, a width of 0.5m, and a height of 1m is:
A. 1.6m2
B. 3.2m2
C. 4.3m2
D. 3.75m2
Solution Method
- Calculate the perimeter of the base = (length + width) x 2.
- The lateral surface area = perimeter of the base x height.
Answer
The perimeter of the base of the rectangular prism is:
(1.1 + 0.5) x 2 = 3.2 (m)
The lateral surface area of the rectangular prism is:
3.2 x 1 = 3.2 (m2)
Answer: 3.2m2.
Choose B
4. Solve problem 4 - Math workbook grade 5 volume 2 page 25
Problem:
A person paints the entire outer surface of a rectangular tin box with a lid. The box has a length of 8 dm, a width of 5 dm, and a height of 4 dm. How many square decimeters are painted?
Solution Method
The total painted area of the tin box is the same as the total surface area of the rectangular box, which includes all six faces.
To find the total surface area of the rectangular box, add the surface area around it to the area of its two bases.
Answer
The total painted area of the tin box is the same as the total surface area of the rectangular box, which includes all six faces.
The perimeter of the base of the rectangular box is:
(8 + 5) x 2 = 26 (dm)
The surface area around the rectangular box is:
26 x 4 = 104 (dm2)
The area of the base of the rectangular box is:
The area of the base is: 8 x 5 = 40 (dm2)
Total painted area is:
104 + 2 x 40 = 184 (dm2)
Answer: 184dm2
5. Solve problem 5 - Workbook math exercise grade 5 volume 2 page 26
Problem statement:
Circle the letter before the correct answer:
How many different ways can you arrange 4 small cubes with edges of 1cm to form a rectangular prism?
A. 1 way
B. 2 ways
C. 3 ways
D. 4 ways
Solution Method
Based on the characteristics of the rectangle to arrange 4 small cubes with a side length of 1cm into a rectangular prism.
Answer
Way 1: Arrange 4 cubes with a side length of 1cm stacked on top of each other (both length and width are 1cm and height is 4cm)
Way 2: Arrange 4 cubes with a side length of 1cm side by side in a row (Length is 4cm, width and height are both 1cm)
So circle the answer B.
You are viewing the guide to Solve math class 5 pages 24, 25, 26 VBT practice 2 Exercise 106, you can review the instructions on Solving math class 5 page 23, 24 VBT practice 2 Surface area and total surface area of the rectangular prism or preview the instructions on Solving math class 5 page 26 VBT practice 2 Surface area and total surface area of the cube to understand more about the lesson.
Good luck with your math studies.
