Buzz
=> Check out more grade 5 math solving materials here: Solving Grade 5 Math
Solving exercises on page 73 of Grade 5 Math Textbook, Focused practice - Includes solving methods
Solving Exercise 1 on page 73 of Grade 5 Math Textbook, Focused Practice
Problem:
Solve:
a) 266.22 : 34; b) 483 : 35;
c) 91.08 : 3.6; d) 3 : 6.25;
Solution Method:
Review the instructions on how to set up division of a decimal by a natural number in Exercise 1 on page 64 of Grade 5 Math Textbook, Focused Practice.
Answer:
Solving Exercise 2 on page 73 of Grade 5 Math Textbook, Focused Practice
Problem:
Solve:
a) (128.4 − 73.2) : 2.4 − 18.32
b) 8.64 : (1.46 + 3.34) + 6.32
Solution Method:
- Perform operations within parentheses first, then outside parentheses.
- When the expression only involves addition and subtraction or multiplication and division, perform operations from left to right.
Answer:
a) (128.4 − 73.2) : 2.4 − 18.32
= 55.2 : 2.4 − 18.32
= 23 − 18.32
= 4.68.
b) 8.64 : (1.46 + 3.34) + 6.32
= 8.64 : 4.8 + 6.32
= 1.8 + 6.32
= 8.12.
Problem:
A motor consumes 0.5 liters of oil per hour. How many hours will the motor run with 120 liters of oil?
Solution Method:
To find out how many hours the engine can run with 120 liters of oil, divide 120 by the number of liters of oil the engine consumes per hour.
Answer:
With 120 liters of oil, the engine can run for the following number of hours:
120 : 0.5 = 240 (hours)
Answer: 240 hours.
Solving Exercise 4 on page 73 of Grade 5 Math Textbook
Problem:
Find x:
a) x - 1.27 = 13.5 : 4.5
b) x + 18.7 = 50.5 : 2.5
c) x x 12.5 = 6 x 2.5
Solution Method:
- Simplify the right-hand side by performing the given calculations.
- Once the correct result is found, proceed to find the variable, specifically:
a) To find the number to be subtracted, take the difference by adding the number to be subtracted.
b) To find the unknown term, take the sum minus the known term.
c) To find the unknown factor, take the product divided by the known factor.
Answer:
a) x - 1.27 = 13.5 : 4.5
x - 1.27 = 3
x = 3 + 1.27
x = 4.27
b) x + 18.7 = 50.5 : 2.5
x + 18.7 = 20.2
x = 20.2 - 18.7
x = 1.5.
c) x x 12.5 = 6 x 2.5
x x 12.5 = 15
x = 15 : 12.5
x = 1.2.
Solving grade 5 math on page 73, focused practice - Concise
Solution for Exercise 1 on page 73 of Math Workbook Grade 5
Calculate:
a) 266.22 ÷ 34; b) 483 ÷ 35;
c) 91.08 ÷ 3.6; d) 3 ÷ 6.25
Solution:
Exercise 2 on page 73 of Math Workbook Grade 5
a) (128.4 – 73.2) ÷ 2.4 – 18.32
b) 8.64 ÷ (1.46 + 3.34) + 6.32.
Solution:
a) (128.4 – 73.2) ÷ 2.4 – 18.32
= 55.2 ÷ 2.4 – 18.32
= 23 – 18.32
= 4.68
b) 8.64 ÷ (1.46 + 3.34) + 6.32
= 8.64 ÷ 4.8 + 6.32
= 1.8 + 6.32
= 8.12
In Chapter I, we familiarize ourselves with various measurement units, with Hectare being one of them. Refer to Math Grade 5 pages 29, 30 for further understanding.
Exercise 3 on page 73 of Math Workbook Grade 5
A motor consumes 0.5 liters of oil per hour. How many hours can the motor run with 120 liters of oil?
Solution:
With 120 liters of oil, the motor can run for:
120 ÷ 0.5 = 240 (hours)
Answer: 240 hours.
Exercise 4 on page 73 of Math Workbook Grade 5
Moreover, Multiplying Decimal Numbers is an important lesson in the Grade 5 Math curriculum that students should pay special attention to.
Above are hints for Math Workbook Grade 5 page 73 exercises, Concentrated Practice with detailed solutions. Prepare for the content of the Percentage Ratio exercise through Math Grade 5 Exercise Solutions page 74 and exercises on Percentage Ratio through Math Workbook Grade 5 page 75 Exercise Solutions for better understanding of Grade 5 Math.
