Guidance on solving exercise 2 on page 137 of Math 5 textbook
Problem:
Calculate:
a) (2 hours 30 minutes + 3 hours 15 minutes) x 3;
2 hours 30 minutes + 3 hours 15 minutes x 3;
b) (5 hours 20 minutes + 7 hours 40 minutes) : 2;
5 hours 20 minutes + 7 hours 40 minutes : 2.
Solution method:
- When the expression contains both addition/subtraction and multiplication/division, perform multiplication/division first, then addition/subtraction.
- When the expression contains parentheses, perform operations within the parentheses first, then outside the parentheses.
Answer:
a) +) (2 hours 30 minutes + 3 hours 15 minutes) x 3
= 5 hours 45 minutes x 3
= 15 hours 135 minutes (135 minutes = 2 hours 15 minutes)
= 17 hours 15 minutes
+) 2 hours 30 minutes + 3 hours 15 minutes x 3
= 2 hours 30 minutes + 9 hours 45 minutes
= 11 hours 75 minutes (75 minutes = 1 hour 15 minutes)
= 12 hours 15 minutes
b) +) (5 hours 20 minutes + 7 hours 40 minutes) : 2
= 12 hours 60 minutes : 2
= 6 hours 30 minutes
+) 5 hours 20 minutes + 7 hours 40 minutes : 2
= 5 hours 20 minutes + 3 hours 50 minutes
= 9 hours 10 minutes
Here is the solution guide for exercise 2 on page 137 of Math 5 textbook's focused practice section. Additionally, this section includes two other exercises: Solve exercise 3 on pages 137, 138 of Math 5 textbook and Solve exercise 4 on pages 137, 138 of Math 5 textbook. Let's check out the guidance for Solve Math 5 exercises on pages 137, 138 to excel in Math class!
