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Guidance on solving Exercise 2 on Page 18 of Mathematics 5 Textbook
Problem:
The quantity of type I fish sauce exceeds that of type II by 12 liters. Inquire about the volume for each type, knowing that the quantity of type I is three times that of type II.
Solution Method:
* Problem Statement:
- Type I fish sauce exceeds type II by 12 liters.
- The quantity of type I fish sauce is three times that of type II.
* The problem requirement: Find the volume of fish sauce for each type.
* Solution Method:
- Summarize the problem using a line graph.
- Find the common difference.
- Determine the smaller number by subtracting the common difference divided by the common difference and then multiply by the smaller number of the difference.
- Determine the larger number by adding the smaller number to the difference.
Answer:
We have the diagram:
According to the diagram, the common difference is:
3 - 1 = 2 (parts)
The quantity of type II fish sauce is
12 : 2 = 6 (liters)
The quantity of type I fish sauce is:
6 + 12 = 18 (liters)
Answer: Type I Fish Sauce: 18 liters ;
Fish sauce type II: 6 liters.
Here is the solution for exercise 2 on page 18 of Mathematics 5 textbook. Additionally, there are two more exercises in this section: Solve Exercise 1 on page 18 of Mathematics 5 and Solve Exercise 3 on page 18 of Mathematics 5. Let's explore the guidance for solving exercises on page 18 of Mathematics 5 to excel in the subject of 5th-grade Mathematics
