Buzz
Solution Guide for Exercise 2 on Page 22 of the 4th-grade Math Workbook
Problem Statement:
a) How many numbers have one digit?
b) How many numbers have two digits?
Solution Method:
- Observations:
+ Single-digit numbers range from 0 to 9.
+ Two-digit numbers range from 10 to 99.
- Solution Approach: To find the number of terms in the sequence, we use the formula:
Number of terms = (Largest term - Smallest term) : d + 1
(Where: d is the unit difference between numbers in the sequence).
- Applying the solution to the exercise: Consecutive numbers in both sequences have a difference of 1.
+ To find the answer to part a, we have: (9 - 0) : 1 + 1 = 10. So, there are 10 single-digit numbers.
+ To find the answer to part b, we have: (99 - 10) : 1 + 1 = 90. So, there are 90 two-digit numbers.
Answer:
a) Single-digit numbers are: 0; 1; 2; 3; 4; 5; 6; 7; 8; 9.
So, there are 10 single-digit numbers.
b) Two-digit numbers are: 10; 11; 12; 13; ...; 97; 98; 99.
So, there are 90 two-digit numbers.
The solution to exercises on page 22 of Math 4 consists of 5 exercises. After solving exercise ewq on page 22 of the Math 4 workbook, please continue to see hints and methods for Solving Exercise 1 on Page 22 of the Math 4 Workbook, Solving Exercise 3 on Page 22 of the Math 4 Workbook, Solving Exercise 4 on Page 22 of the Math 4 Workbook, and Solving Exercise 5 on Page 22 of the Math 4 Workbook to improve your understanding of the subject.
