Solve Exercise 2 on pages 124-125, Mathematics Grade 5 Workbook

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Ngày cập nhật gần nhất: 15/4/2026

Solution for Exercise 2 on pages 124-125, Mathematics Grade 5 Workbook in the Practice Section, Calculating the volume of a cubic shape

Step-by-step guide to solve Exercise 2 on pages 124-125, Mathematics Grade 5 Workbook

Problem:
Given the volume ratio of two cubic shapes is 2 : 3 (refer to the diagram).

a) What percentage of the volume of the large cube is the volume of the small cube?
b) Calculate the volume of the large cube.

Solution Method:
- Given the volume ratio of the two cubes is 2:3 (as stated in the problem) => Express the volume ratio of the large and small cubes, then write it as a percentage ratio
- Calculate the volume of the large cube by multiplying the volume of the small cube by the volume ratio of the large and small cubes.

Answer:
a) The volume ratio of the large and small cubes is 3:2
So, the percentage volume ratio of the large cube to the small cube is:

Above is the solution guide for Exercise 2 on pages 124-125, Mathematics Grade 5 Workbook. Additionally, this section includes two other exercises: Exercise 1 on pages 124-125, Mathematics Grade 5 Workbook and Exercise 3 on pages 124-125, Mathematics Grade 5 Workbook. Check out the guide on Solving Grade 5 Math Exercise on pages 124-125 to excel in 5th-grade Math!

Frequently Asked Questions

How can I calculate the percentage volume of the large cube compared to the small cube?

To calculate the percentage volume of the large cube compared to the small cube, first identify the volume ratio, which is 3:2. Then, express this ratio as a percentage. This means that the large cube's volume represents 60% of the total volume when combined with the small cube.

What method is used to find the volume of the large cube from the small cube's volume?

To find the volume of the large cube based on the small cube's volume, multiply the small cube's volume by the volume ratio of the two cubes, which is 3:2. This calculation will yield the large cube's volume based on the known volume of the small cube.

What is the volume ratio of the large cube to the small cube according to the problem?

The volume ratio of the large cube to the small cube, as stated in the problem, is 3:2. This indicates that for every 2 units of volume in the small cube, the large cube contains 3 units of volume.

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