Solve Exercise 2 Page 108 Math 5 Textbook

Guidelines for Solving Exercise 2 Page 108 Math 5 Textbook

Exercise:
a) Identify equal edges of the rectangular box (side view).
b) Given dimensions of the rectangular box: length 6cm, width 3cm, height 4cm. Calculate area of base MNPQ and side surfaces ABMN, BCPN.

Solution Method:
- Students observe the diagram and identify the equal edges of the rectangular box.
- To calculate the area of the base and the side surfaces, all of which are rectangles, we apply the formula for the area of a rectangle, which is length multiplied by width. 

Answer:
a) AB = MN = QP = DC
    AD = MQ = BC = NP
    AM = BN = CP = DQ
b) The area of the base MNPQ is:
    MN x NP = 6 x 3 = 18 (cm²)
The area of the side surface ABNM is:
    AB x AM = 6 x 4 = 24 (cm²)
The area of the side surface BCPN is:
   BC x CP = 4 x 3 = 12 (cm²)
         Result: b) 18cm², 24cm², 12cm².

Section Solving Math Grade 5 Page 108 consists of 3 exercises, after solving exercise 2 on page 108 of Math 5 Textbook, students can continue to see hints and methods for Solving Exercise 1 Page 108 Math 5 Textbook and Solving Exercise 3 Page 108 Math 5 Textbook, to enhance their understanding of Grade 5 Mathematics.