Guidance to solve Exercise 3 on page 141 of Math 5 textbook
Problem:
A motorcycle travels from point A at 8:20 AM with a speed of 42km/h and arrives at B at 11:00 AM. Calculate the length of segment AB.
Solution Method:
- Given Data:
+ Departure time of the vehicle: 8:20 AM
+ Arrival time of the vehicle: 11:00 AM
+ Speed of the motorcycle: 42 km/h
- Problem Requirement: Calculate the distance AB
- Solution Approach:
+ Calculate the travel time of the motorcycle by subtracting the departure time from the arrival time, convert the result to hours.
+ Calculate the length of segment AB by multiplying the speed of the motorcycle by the travel time of the motorcycle.
Answer:
The travel time of the motorcycle is:
11:00 AM - 8:20 AM = 2 hours 40 minutes
Convert: 2 hours 40 minutes = 8/3 hours
The length of segment AB is:
42 x 8/3 = 112 (km)
Answer: 112km.
Here is the solution guide for exercise 3 on page 141 of Math 5 textbook focusing on practice. Additionally, this section also includes instructions for solving Exercise 1 and Exercise 2 on the same page to help students learn Mathematics Grade 5 effectively.
