Buzz
Guidance for Solving Exercise 3 on Page 19 of Math 5 Textbook
Problem Statement:
The current population of a commune is 4000 people.
a) With an annual increase of 1000 people resulting in an additional 21 people, calculate how many more people the commune will have after one year.
b) If reducing the annual increase to 1000 people results in only 15 additional people, how many more people will the commune have after one year?
Solution Method:
In this problem, you can apply the method of finding ratios to solve:
- Step 1: Perform division to find how many times 4000 people is compared to 1000 people.
- Step 2: Find the number of people added after one year by multiplying the additional people (according to the problem) by the ratio (found in step 1).
- Step 3: Find the population (in question b) by multiplying the additional population when reducing the annual increase by the ratio (result of step 1).
Answer:
+ Summary:
1000 people: increase by 21 people
4000 people: increase by ... people?
+ Solution :
When comparing 4000 people to 1000 people, it is:
4000 : 1000 = 4 (times)
After one year, the population of the commune increases by
21 x 4 = 84 (people)
Answer: 84 people
b) Summary
1000 people: increase by 15 people
4000 people increase by ... people?
After one year, the population of the commune increases by:
4000 x 15 / 1000 = 60 (people)
Answer: 60 people.
Here is the solution guide for Exercise 3 on Page 19 of Math 5 Textbook. Additionally, there are 2 other exercises: Solve Exercise 1 on Page 19 of Math 5 Textbook and Solve Exercise 2 on Page 19 of Math 5 Textbook. Let's check out the solution guide for exercises on Page 19 Math 5 to excel in 5th-grade math.
