Guidance on solving exercise 3 on page 50 of Math 5 textbook practice
Problem:
A rectangle has a width of 16.34m, and its length is 8.32m more than its width. Calculate the perimeter of that rectangle.
Solution Method:
- The problem details:
+ Width: 16.34 m
+ Length is 8.32 m more than the width
- The problem requirement: Calculate the perimeter of the rectangle.
- How to solve:
+ Find the length of the rectangle by adding the width measurement to the measurement by which the length exceeds the width.
+ Calculate the perimeter of the rectangle by adding the given width to the found length, multiplied by 2.
Answer:
The length of the rectangle is:
16.34 + 8.32 = 24.66 (m)
The perimeter of the rectangle is:
(24.66 + 16.34) x 2 = 82 (m)
Answer: 82 m.
Here is the solution guide for Exercise 3 on page 50 of Math 5 textbook practice. Additionally, this section includes 3 more exercises: Solve Exercise 1 on Page 50 of Math 5 Textbook Practice, Solve Exercise 2 on Page 50 of Math 5 Textbook Practice, and Solve Exercise 4 on Page 50 of Math 5 Textbook Practice. Let's explore the guide to solve exercises on page 50 Math 5 practice to excel in 5th-grade Mathematics!
