Solve Exercise 3 Page 48 Math 4

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Ngày cập nhật gần nhất: 15/4/2026

Solve Exercise 3 Page 48 Math 4 in Practice, Calculate using the most convenient method:

Guidelines for solving Exercise 3 Page 48 Math 4

Problem:
Calculate using the most convenient method:
a) 98 + 3 + 97 + 2 b) 364 + 136 + 219 + 181
56 + 399 + 1 + 4 178 + 277 + 123 + 422

Explanation Method: - Group the terms in the given expression into groups with sums that are multiples of ten/hundred/thousand. - Apply the associativity property of addition: When adding the sum of two numbers to a third number, add the first number to the sum of the second and third numbers.

Answers: a) 98 + 3 + 97 + 2 = 200 b) 364 + 136 + 219 + 181 = 1000.

Section solving exercises page 48 math 4, focused practice consists of 5 exercises. Next, solving Exercise 3 Page 48 Math 4. Mytour suggests answer and detailed solution methods for Solving Exercise 1 Page 48 Math 4 practice, Solving Exercise 2 Page 48 Math 4 practice, Solving Exercise 4 Page 48 Math 4 practice, and Solving Exercise 5 Page 48 Math 4 practice, students need to grasp the knowledge of this lesson.

Frequently Asked Questions

What are the steps to solve Exercise 3 on Page 48 of Math 4?

To solve Exercise 3 on Page 48 of Math 4, group terms into sums that are multiples of ten, hundred, or thousand. Then, use the associativity property of addition for efficient calculation.

How can I calculate sums like 98 + 3 + 97 + 2 efficiently?

You can calculate sums like 98 + 3 + 97 + 2 by grouping numbers strategically. For example, 98 + 2 makes 100, and 3 + 97 makes 100, leading to a total of 200.

What is the final answer for part b of Exercise 3, Page 48?

The final answer for part b of Exercise 3 is 1000. This is achieved by adding the numbers 364, 136, 219, and 181 together using strategic grouping.

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