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Guidance for solving exercises on page 18 Mathematics Grade 5 includes solution methods
1. Solve Exercise 1 on Page 18 of Math 5 Textbook
Problem:
a) The sum of two numbers is 80. The first number is 7/9 of the second number. Find these two numbers.
b) The difference between two numbers is 55. The first number is 9/4 of the second number. Find these two numbers.
Solution Method:
1. Approach to solving Sum - Ratio problems:
- Summarize the problem using a line segment diagram (ensuring that the line segments have equal lengths)
- Find the total number of equal parts
- Find the value of one part by dividing the sum by the total number of equal parts.
- Find the smaller number by multiplying the value of one part by the number of parts of the smaller number.
- Find the larger number by multiplying the value of one part by the number of parts of the larger number.
2. Approach to solving Difference - Ratio problems:
- Summarize the problem using a line segment diagram (ensure that the line segments are of equal length)
- Find the difference in the number of equal parts
- Find the value of one part by dividing the difference by the difference in the number of equal parts.
- Find the smaller number by multiplying the value of one part by the number of parts of the smaller number.
- Find the larger number by multiplying the value of one part by the number of parts of the larger number.
Answer:
a) We have the diagram:
According to the diagram, the total number of equal parts is:
7 + 9 = 16 (parts)
The first number is:
80 : 16 x 7 = 35
The second number is:
80 - 35 = 45
Answer: 35 and 45.
b) We have the diagram:
According to the diagram, the difference in the number of equal parts is:
9 - 4 = 5 (parts)
The second number is :
55 : 5 x 4 = 44
The first number is:
44 + 55 = 99
Answer: 99 and 44.
2. Solve exercise 2 on page 18 Mathematics Grade 5 textbook
Problem:
The quantity of fish sauce of type I exceeds the quantity of fish sauce of type II by 12 liters. How many liters of fish sauce does each type have, knowing that the quantity of fish sauce of type I is three times the quantity of fish sauce of type II?
Solution Method:
* Problem statement:
- Fish sauce of type I exceeds fish sauce of type II: 12 liters
- The quantity of fish sauce of type I is three times the quantity of fish sauce of type II
* The problem requires: Find the quantity of fish sauce for each type.
* Solution approach:
- Summarize the problem using a line segment diagram
- Find the difference in the number of equal parts
- Find the smaller number by dividing the difference by the difference in the number of equal parts and then multiplying by the number of parts of the smaller number
- Find the larger number by adding the smaller number to the difference.
Answer:
We have the diagram:
According to the diagram, the difference in the number of equal parts is:
3 - 1 = 2 (parts)
The quantity of fish sauce type II is
12 : 2 = 6 (liters)
The quantity of fish sauce type I is:
6 + 12 = 18 (liters)
Answer: Fish sauce type I: 18 liters ;
Fish sauce type II: 6 liters.
3. Solve exercise 3 on page 18 Mathematics Grade 5 textbook
Problem:
A rectangular flower garden has a perimeter of 120m. The width is 5/7 of the length.
a) Calculate the length and width of the flower garden.
b) 1/25 of the garden area is used for the pathway. How many square meters is the area of the pathway?
Solution Method:
- Step 1: Summarize the problem using a line segment diagram.
Step 2: Find the total number of equal parts.
Step 3: Find the smaller number by dividing the total by the number of equal parts, then multiply it by the number of parts of the smaller number.
Step 4: Find the larger number by subtracting the smaller number from the total.
* Note: In this problem, we are given the perimeter of a rectangle: P = (a + b) x 2. So, first, we need to find the sum of the length and width by finding half of the perimeter of the rectangle.
Answer:
a) Half the perimeter or the sum of the length and width is:
120 ÷ 2 = 60 (m)
We have the diagram:
According to the diagram, the total number of equal parts is:
5 + 7 = 12 (parts)
The width of the flower garden is:
60 ÷ 12 x 5 = 25 (m)
The length of the flower garden is:
60 − 25= 35 (m)
b) The area of the flower garden is:
35 x 25 = 875 (m2)
The area of the pathway is:
875 ÷ 25 = 35 (m2)
The answer is:
a) Length: 35m;
Width: 25m;
b) 35m2
Concise solution for exercise on page 18 Mathematics Grade 5
Solve exercise 1 page 18 Math 5 textbook
Solving Exercise 2 on page 18 of Math Workbook Grade 5
In Chapter I, we acquaint ourselves with measurement units, among which Hectares are frequently used. Let's explore hints for solving exercises on pages 29 and 30 of Math Workbook Grade 5 to excel in Grade 5 Mathematics.
Solving Exercise 3 on page 18 of Math Workbook Grade 5
Above are suggestions for Solving exercises on page 18 of Grade 5 Mathematics Workbook with detailed explanations. Prepare yourselves with review content and supplement your problem-solving skills with Solving exercises on page 19 of Grade 5 Mathematics Workbook and practice problems on pages 19 and 20 of Math Workbook Grade 5 through Solving exercises on pages 19 and 20 of Grade 5 Mathematics Workbook to enhance your understanding of Grade 5 Mathematics.
In addition to the above content, you can explore the section on Solving exercises on page 64 of Math Workbook Grade 5 to enhance your knowledge of Grade 5 Mathematics.
Furthermore, Solving exercises on page 66 of Math Workbook Grade 5 is an important lesson in the Grade 5 Mathematics curriculum that you should pay special attention to.
