Solve exercises on page 79-80 of Math 3 Book 1, connecting knowledge with life

Solve Math Grade 3 page 79-80 Workbook 1, connecting knowledge with life

Solve exercises on page 79-80 of Math 3 Book 1, connecting knowledge with life:

Decreasing a Number Multiple Times

Activity

1. Solve Exercise 1 Page 79 Math Grade 3 Textbook

Problem: Number?

Guidance:
To reduce a number multiple times, divide the number by the times.
To increase a number multiple times, multiply the number by the times.

Answer:

2. Solve Exercise 2 Page 79 Math Grade 3 Textbook

Problem: Nam has 42 notebooks. After giving some notebooks to his friends, the remaining notebooks for Nam are reduced by 3 times compared to the initial amount. How many notebooks does Nam have left?

Guidance: The remaining notebooks for Nam = Initial notebooks : 3

Answer:
Nam has
               42 : 3 = 14 (notebooks)
                                Final Answer: 14 notebooks.

Practice

1. Solve Exercise 1 Page 80 Math Grade 3 Textbook

Problem: Number ?

Guidance:
To decrease a number multiple times, divide the number by the times.
To increase a number multiple times, multiply the number by the times.

Answer:

2. Solve Exercise 2 Page 80 Math Grade 3 Textbook

Problem: What is the route for the robot to have 40 gold coins?

Guidance:
To decrease a number multiple times, divide the number by the times.
To increase a number multiple times, multiply the number by the times.

Answer:

We have:

So, the route for the robot to have 40 gold coins is:

3. Solve Exercise 3 Page 80 Mathematics Grade 3 Textbook

Problem: How many colored pencils does Mai have left?

Solution: The remaining colored pencils for Mai = The initial number of colored pencils Mai had : 4

The solution is:
Mai has
                 28 : 4 = 7 (color pencils)
                              Answer: 7 color pencils.

4. Solve Problem 4 on page 80 of Math 3 Textbook

Problem: Find the divisor.

To find the divisor, divide the dividend by the quotient.

54 : ? = 6
54 : 6 = 9
So the missing number is 9.
56 : ? = 7
56 : 7 = 8
So the missing number is 8.
36 : ? = 9
36 : 9 = 4
So the missing number is 4.

Solving exercises on pages 79 and 80 of Math 3 Volume 1 textbook, Connecting Knowledge with Life, provides detailed solutions to exercises 1, 2, 3, and more. Hopefully, students can easily visualize the correct approach to solving similar math problems.