Solution Guide for Exercise 5 on pages 147 and 148 in the Math 5 textbook
Problem:
Find the appropriate digits to complete the following:
a) ...43 divisible by 3;
b) 2...7 divisible by 9;
c) 81... divisible by both 2 and 5;
d) 46... divisible by both 3 and 5.
Solution Approach:
- Divisibility indicator for 3: The sum of the digits must be divisible by 3 => The number is divisible by 3.
- Divisibility indicator for 9: The sum of the digits must be divisible by 9 => The number is divisible by 9.
- Divisibility indicator for both 2 and 5: The last digit is 0 => The number is divisible by both 2 and 5.
- Divisibility indicator for both 3 and 5: The sum of the digits must be divisible by 3 and the last digit is 5 => The number is divisible by both 3 and 5.
Answer:
a) ....43 is divisible by 3, so ....+ 4 + 3 = .... + 7 is divisible by 3. Therefore, the blank can be filled with one of the digits: 2, 5, 8.
b) Similarly, 2 + ....+ 7 = 9 +.... is divisible by 9. Therefore, the blank can be filled with 0 or 9.
c) For 81..., to be divisible by both 2 and 5, ... must be 0. Therefore, write 0 in the blank.
d) Since 46.... is divisible by 5, .... can be 0 or 5.
- If .... is 0, then 4 + 6 + 0 = 10 is not divisible by 3: reject.
- If .... is 5, then 4 + 6 + 5 = 15 is divisible by 3: select.
Therefore, write the digit 5 in the blank.
Here is the solution guide for Exercise 5 on page 148 in the Math 5 textbook, focusing on concentrated practice. Additionally, this section contains 4 more exercises: Solve Exercise 1 on pages 147 and 148 in Math 5, Solve Exercise 2 on pages 147 and 148 in Math 5, Solve Exercise 3 on pages 147 and 148 in Math 5, and Solve Exercise 4 on pages 147 and 148 in Math 5. Let's explore the solution guide for Math Grade 5 pages 147, 148 to excel in the subject of Math Grade 5.
