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Study material for solving 4th-grade math on page 152, including solution methods and corresponding answers to exercises in the textbook. It helps students review and organize knowledge on finding two numbers given their sum, difference, and ratio. Below are detailed solutions for math 4 on page 152. Please follow along, compare methods, and enhance your own work.
=> Reference for Solving 4th Grade Math Here: Solve 4th Grade Math
Guide to solving 4th-grade math on page 152: Focused practice (Including solution methods)
1. Solving math 4 on page 152, focused practice, exercise 1
Problem:
Solution Method:
- Step 1. Represent the larger and smaller numbers based on the ratio of the two numbers using equal parts
- Step 2. Find the difference of equal parts
- Step 3. Find the value of one part by dividing the difference of two numbers by the difference of equal parts
- Step 4. Find the smaller and larger numbers based on the corresponding difference of equal parts
Answer:
2. Solving 4th-grade math on page 152, focused practice, exercise 2
Problem:
The difference of two numbers is 738. Find the two numbers, knowing that the first number, when decreased by 10 times, equals the second number.
Solution Method:
- Step 1: As per the problem, when the first number is decreased by 10 times, it becomes the second number. Therefore, the ratio of parts for the first and second numbers is 10/1
- Step 2: Illustrate: Let the second number (smaller number) be 1 part, then the first number (larger number) will consist of 10 parts.
- Step 3: Calculate the value of one part based on the difference of equal parts and the total number of parts
- Step 4: Calculate the values of the first and second numbers based on the corresponding number of equal parts.
Answer:
The first number, when decreased by 10 times, becomes the second number. Therefore, the first number is 10 times greater than the second number, or the second number is 1/10 of the first number.
According to the illustration, the difference in the number of equal parts is: 10 - 1 = 9 (parts)
The second number is: 738 : 9 × 1 = 82
The first number is: 82 × 10 = 820
Answer: First number: 820; Second number: 82
3. Solving 4th-grade math, focused practice on page 152, exercise 3 in the textbook
Problem:
There are 10 bags of glutinous rice and 12 bags of plain rice, with a total weight of 220kg. Knowing that the weight of rice in each bag is the same. How many kilograms of rice are there for each type?
Solution Method:
- Step 1. Calculate the total number of bags of glutinous rice and plain rice
- Step 2: Calculate the number of kilograms of rice in each bag
- Step 3: Calculate the weight of plain rice, glutinous rice corresponding to the number of bags of each type.
Answer:
The total number of bags of glutinous rice and plain rice is: 10 + 12 = 22 (bags)
The weight of rice in each bag is: 220 : 22 = 10 (kg)
The weight of glutinous rice is: 10 × 10 = 100 (kg)
The weight of plain rice is: 10 × 12 = 120 (kg)
Answer: Weight of glutinous rice: 100 (kg), weight of plain rice: 120 (kg)
4. Solving 4th-grade math, concentrated practice on page 152
Solution Method:
- Step 1: Let's call the distance from An's house to the bookstore 3 units. According to the given conditions, the distance from the bookstore to An's school will be 5 units.
- Step 2: Calculate the total number of units
- Step 3: Determine the value of one unit
- Step 4: Calculate the distance from An's house to the bookstore and the distance from the bookstore to An's school based on the corresponding units.
Answer:
Let's designate the distance from An's house to the bookstore as 3 units. According to the given conditions, the distance from the bookstore to An's school will be 5 units.
Thus, the total number of units is: 3 + 5 = 8 (units)
The length of the road from An's house to the bookstore is: 840 : 8 × 3 = 315 meters
The length of the road from the bookstore to the school is: 840 – 315 = 525 meters
Answer:
- The distance from An's house to the bookstore: 315m
The distance from the bookstore to School An is 525 meters.
Mathematics guide for 4th grade page 152 concise practice
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Here is the detailed answer, solution for 4th-grade math page 152. If students are not familiar with how to apply the formula to find two numbers when given their sum, difference, and the ratio between them, they can ask the teacher, have friends explain, or explore materials on solving math problems on page 152 in the concentrated practice to learn how to solve and apply it in their exercise process.
In addition, students can review the 4th-grade math problems on page 151 that have been solved before or preview the 4th-grade math problems on page 153 to improve their understanding of the subject.
