Solving 4th-grade math page 86, Division by a Three-Digit Number, Exercises 1, 2, 3

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Guidance on solving 4th-grade math page 86 (including solution methods)

Division by a Three-Digit Number

1. Solving Math Problem 4 on page 86 Exercise 1

2. Solving Math Problem 4 on page 86 Exercise 2

3. Solving 4th-grade math problem 3 on page 86

Practice 4th-grade math problem-solving concise

B. EXERCISES AND SOLUTIONS

Unlock the secrets of 4th-grade math page 86 in the textbook, covering exercises 1, 2, 3 of the lesson Division by a Three-Digit Number. This invaluable resource aids easy revision, knowledge consolidation, and precise homework solutions. Refer to it for seamless and accurate at-home assignments.

=> Explore more 4th-grade math problem-solving here: 4th-grade math problems

Guidance on solving 4th-grade math page 86 (including solution methods)

Division by a Three-Digit Number

1. Solving Math Problem 4 on page 86 Exercise 1

Problem Statement:
Set up and solve the following division problems:
a) 2120 : 424; 1935 : 354
b) 6420 : 321; 4957 : 165

Solution Method:
Method for setting up the division of a number with multiple digits by a three-digit number:
- Set up the calculation in a vertical column
- Take the first three digits of the dividend (if these three digits are larger than the divisor) or the first four digits (if the first three digits are smaller than the divisor) and divide them by the divisor. Multiply the quotient by the divisor
- Subtract the three/four digits of the dividend by the product obtained

2. Solving Math Problem 4 on page 86 Exercise 2

Problem Statement:
Calculate the value of the expression:
a) 1995 x 253 + 8910 : 495 b) 8700 : 25 : 4

Solution Method:

- For part a): This expression involves addition, multiplication, and division. Perform multiplication and division first, then addition
- For part b): This expression involves only division. Perform the calculation from left to right.

Answer:
a) 1995 x 253 + 8910 : 495
= 504735 + 18
= 504753
b) 8700 : 25 : 4
= 8700 : (25 x 4)
= 8700 : 100 = 87

3. Solving 4th-grade math problem 3 on page 86

Problem Statement:
There are two stores, each receiving 7128m of fabric. On average, the first store sells 264m of fabric per day, and the second store sells 297m. Which store sells out of the fabric sooner and by how many days?

Solution Method:
- Calculate the number of days it takes for the first store to sell all the fabric by dividing the received fabric by the average fabric sold per day by the first store
- Similarly, calculate the number of days it takes for the second store to sell all the fabric by dividing the received fabric by the average fabric sold per day by the second store
- To determine which store sells out sooner and by how many days, compare the two results and subtract the smaller number from the larger one.

Answer:
The first store sells out in days:
7128 : 264 = 27 (days)
The second store sells out in days:
7128 : 297 = 24 (days)
So, the second store sells out sooner and by days:
27 - 24 = 3 ( days )
Answer: 3 days

Practice 4th-grade math problem-solving concise

A. THEORY

B. EXERCISES AND SOLUTIONS

Question 1: Page 86 Math Book Grade 4

Set up and solve the following division problems:
a) 2120 : 424; 1935 : 354
b) 6420 : 321; 4957 : 165

Solution:

Question 2: Page 86 Math Book Grade 4
Calculate the value of the expression:
a) 1995 x 253 + 8910 : 495
b) 88700 : 25 : 4
Solution:
Note: Children should follow the rule of multiplication and division first, addition and subtraction later.
a) 1995 x 253 + 8910 : 495
= 504735 + 18
= 504753
b) 8700 : 25 : 4
= 8700 : (25 x 4)
= 8700 : 100
= 87

Question 3: Page 86 Math Book Grade 4
There are two stores, each receiving 7128m of fabric. On average, the first store sells 264m of fabric per day, and the second store sells 297m. Which store sells out of the fabric sooner and by how many days?

Solution:

The first store sells out in days:
7218 : 264 = 27 (days)

The second store sells out in days:
7128 : 297 = 24 (days)

So, the second store sells out sooner and by days:
27 - 24 = 3 (days)

So, the second store sells out earlier by 3 days compared to the first store.

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Here is the solution to the 4th-grade math problem on page 86 of the textbook. Next, for further practice on division, students can review the solution to the 4th-grade math problem on page 85 of the textbook solved earlier or preview the solution to the 4th-grade math problem on page 87 to excel in 4th-grade Math.

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Frequently Asked Questions

What are the key methods for solving division problems by three-digit numbers in 4th grade?

To solve division problems by three-digit numbers, first set up the calculation in a vertical column. Then, use the first three or four digits of the dividend as needed. Divide these digits by the divisor, multiply the quotient by the divisor, and subtract this product from the initial digits of the dividend to find the remainder.

How do students calculate the value of complex expressions involving multiplication and division?

Students should follow the order of operations when calculating complex expressions. For multiplication and division, perform those operations first, followed by addition. For example, in the expression 1995 x 253 + 8910 : 495, multiply and divide first, then sum the results for an accurate answer.

Which store sells out of fabric sooner and by how many days according to the math problem?

According to the math problem, the second store sells out of the fabric sooner. The first store takes 27 days to sell its fabric, while the second store only takes 24 days, resulting in the second store selling out 3 days earlier than the first store.

How can students effectively revise 4th-grade math problems for better understanding?

Students can effectively revise 4th-grade math problems by practicing exercises that reinforce their understanding. Utilizing resources like solution guides for specific textbook pages allows them to consolidate knowledge and understand various problem-solving methods for concepts such as division by three-digit numbers.