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Step-by-step guide to solving 4th-grade math problems on page 98 (including solution methods)
1. Solving 4th-grade math problem on page 98 in the textbook, exercise 1
Problem:
Among the following numbers, which ones are divisible by 3?
231; 109; 1872; 8225; 92313
Solution Method:
Divisibility rule for 3: Similar to the divisibility rule for 9, a number whose sum of digits is divisible by 3 is itself divisible by 3.
=> Approach: Add up all the digits in the number, then divide the sum by 3. If it divides evenly, conclude that the number is divisible by 3.
+) Number 231 has a digit sum of 2 + 3 + 1 = 6.
2. Solving 4th-grade math problem 2 on page 98 in the textbook
Write three three-digit numbers that are divisible by 3
To solve:
Divisibility rule for 3: If the sum of the digits is divisible by 3, the number is divisible by 3.
The answers could be: 351; 648; 891.
Solve the problem on page 98, question 4 for 4th-grade students.
Divisibility Rules Recap:
- Key points to remember:
+ Divisible by 3: The sum of the digits must be divisible by 3.
+ Divisible by 9: The sum of the digits must be divisible by 9.
Answers:
Quick Guide to Solve 4th-grade Math on Page 98
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Explore the solution to the 4th-grade math problem on page 98 in the textbook, curated by Mytour. Additionally, students can review the Practice Solutions for 4th-grade Math on page 98 or preview the Solutions for 4th-grade Math on page 99 to enhance their understanding of the subject. Best wishes for successful learning!
