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Step-by-step guide to solving 4th-grade Mathematics on pages 123,124. Includes solution methods.
To solve the problem stated on pages 123 and 124 of the textbook, exercise 1: Find the appropriate digits to fill in the blanks so that: a) 75... is divisible by 2 but not by 5. b) 75... is divisible by both 2 and 5. Is the resulting number divisible by 3? c) 75... is divisible by 9. Does the resulting number divide evenly by both 2 and 3?
a) The possible digits to fill in the blank are: 2, 4, 6, 8, which yield the numbers: 752, 754, 756, 758. b) To be divisible by 2 and 5, the digit in the units place must be 0. Thus, filling in the blank with 0 gives us 750. Now, 7 + 5 + 0 = 12; 12 is divisible by 3. Therefore, 750 is divisible by 3. c) For 756 to be divisible by 9, the sum of 7 + 5 + ... must be divisible by 9, or 12 + ... must be divisible by 9. Hence, filling in the blank with 6 gives us 756. Since the units digit of 756 is 6, it is divisible by 2, and since the sum of its digits is 18, it is divisible by 3. Therefore, 756 is divisible by both 2 and 3.
Solution method: - A number divisible by 5 has a units digit of 0 or 5. - A number divisible by both 2 and 5 has a units digit of 0. - A number divisible by 3 has a sum of digits divisible by 3. - A number divisible by 9 has a sum of digits divisible by 9. - A number divisible by both 2 and 3 satisfies two conditions simultaneously: the sum of its digits is divisible by 3, and the units digit is one of: 0, 2, 4, 6, 8.
a) The digits 2, 4, 6, 8 can be placed in the blank, resulting in: 752, 754, 756, 758. b) For a number to be divisible by both 2 and 5, the units digit must be 0. Thus, filling in the blank with 0 gives us 750. Then, 7 + 5 + 0 = 12; 12 is divisible by 3. Hence, 750 is divisible by 3. c) To make 756 divisible by 9, the sum of 7 + 5 + ... must be divisible by 9, or 12 + ... must be divisible by 9. Therefore, filling in the blank with 6 gives us 756. Since the units digit of 756 is 6, it is divisible by 2, and since the sum of its digits is 18, it is divisible by 3. Therefore, 756 is divisible by both 2 and 3.
Solving Class 4 Math Problems on pages 123 and 124, focusing exercise, question 2
Problem Statement:
Each class has 14 male students and 17 female students.
a) Write a fraction representing the portion of male students among the total students in that class.
b) Write a fraction representing the portion of female students among the total students in that class.
Solution Approach:
- Calculate the total number of students in the class by adding the number of male and female students.
- Fraction representing the portion of male students among the total students in the class: The numerator is the number of male students (given in the problem statement), the denominator is the total number of students in the class.
- Fraction representing the portion of female students among the total students in the class: The numerator is the number of female students (given in the problem statement), the denominator is the total number of students in the class.
Answer:
The total number of students in the class is: 14 + 17 = 31 students
a) The fraction representing the portion of male students among the total students in the class is: 14/31.
b) The fraction representing the portion of female students among the total students in the class is: 17/31.
Solving 4th grade math exercises on pages 123 and 124 of the textbook, exercise 3.
To solve: Simplify the given fractions by dividing both the numerator and denominator by the same number different from 1, then compare with the fraction 5/9.
Exercise 4: Solving 4th grade math problems on pages 123 and 124 of the textbook.
To solve: Step 1: Simplify the given fractions into their simplest forms. Step 2: Find a common denominator for the simplified fractions to make them have the same denominator.
Solving Puzzle 5, Math Solution for Grade 4, pages 123, 124 in the textbook.
Problem: Two rectangles share a common part, forming quadrilateral ABCD (see diagram).
a) Explanation: Quadrilateral ABCD has each pair of opposite sides parallel.
b) Measure the lengths of the sides of quadrilateral ABCD, then determine whether each pair of opposite sides are equal.
c) Given that quadrilateral ABCD is a parallelogram with a base length of 4cm and a height of 2cm. Calculate the area of parallelogram ABCD.
Solution Method:
Using a ruler, measure the lengths of the sides of quadrilateral ABCD and make observations.
Answer:
a) Since AB and CD belong to the opposite sides of the rectangle horizontally, AB is parallel to CD. AD and BC belong to the opposite sides of the rectangle diagonally, so AD is parallel to BC.
b) Measuring the sides of quadrilateral ABCD with a ruler, we find: AB = CD = 4cm and AD = BC = 3cm. Therefore, quadrilateral ABCD has pairs of opposite sides equal.
The area of parallelogram ABCD is 8 square centimeters.
Solve exercise 1 from the fourth-grade math textbook on pages 123 and 124.
Problem statement:
Find the suitable digit to fill in the blank so that:
a) 75 ... is divisible by 2 but not divisible by 5.
b) 75.. is divisible by 2 and divisible by 5.
Is the number found divisible by 3?
Is 75 divisible by 9?
Does the number found divide by both 2 and 3?
Answer:
To make 75 divisible by 2, you need to fill in the blank with one of these digits: 0, 2, 4, 6, 8.
To ensure divisibility by 5, insert either 0 or 5 into the blank space; however, 75 is divisible by 2 as well, so only 0 can fill the gap: 750.
To make 75 divisible by 5, fill the blank with either 0 or 5.
However, since 75 is also divisible by 2, fill the blank with the digit 0: 750.
For 75 to be divisible by 9, we need:
* Solving exercise 2 for 4th grade mathematics, focusing on pages 123, 124 of the textbook
Problem statement:
There are 14 male students and 17 female students in a class.
a) Express the fraction representing the number of male students out of the total number of students in the class.
b) Express the fraction representing the ratio of female students to the total number of students in the class.
Answer:
* Solve exercise 3 in the math workbook for 4th graders focusing on pages 123, 124
Problem Statement:
Answer:
Solution for exercise 4 in math, pages 123, 124, focusing on textbook exercises
Problem statement:
Response:
Solving math exercises for 4th grade on pages 123 and 124, focusing on textbook practice
Task description:
A rectangle with a common section forming quadrilateral ABCD (see diagram).
a) Explain why quadrilateral ABCD has opposite sides parallel.
b) Measure the lengths of the sides of quadrilateral ABCD and comment on whether each pair of opposite sides is equal or not.
c) Given that quadrilateral ABCD is a parallelogram with a base length of DC being 4cm and a height of AH being 2cm. Calculate the area of parallelogram ABCD.
Answer:
a) Sides AB and CD belong to the two opposite sides of the rectangle (horizontal) so they are parallel to each other.
The edges DA and BC belong to the opposite sides of the slanted rectangle, thus they run parallel to each other.
Consequently, quadrilateral ABCD exhibits pairs of opposite sides running parallel to each other.
b) Following this, we have:
AB measures 4cm;
AB measures 4 centimeters;
AD is 3 centimeters in length;
BC equals 3 centimeters;
Thus, AB is equal to CD, and AD is equal to BC.
As a result, we find that the quadrilateral has pairs of opposite sides equal.
c) Area of the parallelogram: 4x2=8cm2.
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Here we have explored the solution to Grade 4 math problem on pages 123, 124, with a concise and understandable approach. Next, students should delve into solving Grade 4 math problem on page 122 or refer to the hints for solving problems 124, 125 from the Math 4 Consolidation page 124, 125 of Grade 4 Math textbook to excel in Math 4.
