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Students are looking for guidance on solving exercises 1, 2 on pages 18, 19 of the 5th-grade Math workbook. Let's explore the document 'Solving 5th-grade math problems on pages 18, 19 of VBT Workbook 2, Continuing practice on calculating area, exercise 102.' All solutions are detailed and closely aligned with the curriculum.
Solving 5th-grade math problems on pages 18, 19 of VBT Workbook 2, Continuing practice on calculating area, exercise 102
1. Solve Exercise 1 - Math 5 Exercise Workbook 2 Page 18
Problem Statement:
Calculate the area of the land plot with dimensions as shown below:
Solution Method:
- Divide the land plot into a square (1), a rectangle (2), and another rectangle (3) as illustrated in the solution.
The area of the land plot is the sum of the areas of shapes (1), (2), and (3).
- Apply the following formulas:
+ Area of a square = side x side.
+ Area of a rectangle = length x width.
Answer
Divide the land plot into a square (1), a rectangle (2), and another rectangle (3) as shown in the diagram.
The area of square (1) is:
5x5=25(m
2)
The length of rectangle (2) is:
6+5=11(m)
The area of rectangle (2) is:
6x11=66(m2)
The width of rectangle (3) is:
16−5−6=5(m)
The length of rectangle (3) is:
7+6+5=18(m)
The area of rectangle (3) is:
18x5=90(m2)
The area of the land plot is:
25+66+90=181(m2)
Answer: 181m2
2. Solve Exercise 2 - Math 5 Exercise Workbook 2 Page 19
Problem Statement:
Calculate the area of the land plot with dimensions as shown below, knowing:
Given: BM = 14m, CN = 17m, EP = 20m
Given: AM = 12m, MN = 15m, ND = 31m
Solution Method
- Divide the land plot into triangles ABM, trapezoid BCMN, triangle CND, triangle ADE.
The area of the land plot is the sum of the areas of the shapes above.
- Applying the following formulas:
+ Area of a triangle = base length x height : 2.
+ Area of a right triangle = length of first perpendicular side x length of second perpendicular side : 2.
The area of a trapezoid = (sum of the lengths of the parallel sides) x height : 2.
Answer
The area of triangle ABM is:
12 x 14 : 2 = 84 (m2)
The area of trapezoid BCNM is:
(14+17) x 15/2 = 232.5 (m2)
The area of triangle CND is:
31 x 17 : 2 = 263.5 (m2)
The area of triangle ADE is:
(12 + 15 + 31) x 20 : 2 = 580 (m2)
The area of the land plot is:
84 + 232.5 + 263.5 + 580 = 1160 (m2)
Answer: 1160m2 You are currently viewing the guidance for solving 5th-grade math problems on pages 18 and 19 of VBT Workbook 2, Practice on calculating area (continued), exercise 102. You can review the instructions for solving 5th-grade math problems on pages 17 and 18 of VBT Workbook 2, Practice on calculating area or preview the guidance for solving 5th-grade math problems on page 21 of VBT Workbook 2 for a better understanding of the lesson.
Wishing you all the best in learning mathematics.
