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Solving Class 4 Math Problem on Pages 60, 61 of VBT Workbook Volume 2, Concentrated Practice, Exercise 136 provides detailed solutions and guidance for exercises 1, 2, 3, and 4, making it easy for students to review how to identify rhombuses and apply the formula for calculating rhombus area.
Solving Class 4 Math Problem on Pages 60, 61 of VBT Workbook Volume 2, Concentrated Practice, Exercise 136
1. Solve Exercise 1 - Class 4 Math Workbook Volume 2 Exercise on Page 60
Problem Statement:
Continue writing in the blank:
In rectangle ABCD:
a) AB is parallel to .........
b) BC is parallel to .........
c) DA is perpendicular to .........
d) DC is perpendicular to .........
Solution Approach
Observe the diagram to determine which edges are parallel to each other, and which edges are perpendicular to each other.
Answer
a) AB is parallel to DC
b) BC is parallel to AD
c) DA is perpendicular to AB, DC
d) DC is perpendicular to CB, DA
2. Solve Exercise 2 - Math workbook for Grade 4 Exercise 2 on page 60
Problem Statement:
Fill in the blank:
In the rhombus PQRS:
a) PQ is opposite to ..........
b) PQ is parallel to ..........
c) PQ = ..........= .......... = ..........
d) PQ is not parallel to .......... and ..........
Solution Approach
Observe the rhombus carefully to answer the questions in the problem.
Answer
a) PQ is the side opposite to SR
b) PQ is parallel to SR
c) PQ = QR = RS = SP
d) PQ is not parallel to QR and PS
3. Solve Problem 3 - Math Workbook for Grade 4 Exercise 2 Page 60
Problem Statement
Among the following shapes, which one has a different area compared to the rest:
Solution Approach
Calculate the area of each shape and then compare the results:
- Area of a square = side x 4.
- Area of a rectangle = length x width.
- Area of a rhombus = product of the lengths of its diagonals ÷ 2.
Answer
The area of the square is:
6 x 6 = 36 (cm2)
The area of the rectangle is:
6 x 9 = 54 (cm2)
The area of the rhombus is:
(6 x 18) : 2 = 54 (cm2)
The area of the square differs from the areas of the other two shapes.
4. Solve problem 4 - Math workbook for Grade 4, Exercise 2, page 61
Problem
A rectangle has a length of 16cm and a width of 10m. If the length increases by 4m, what will be the new area of the rectangle in square meters?
Solution Approach
- Calculate the new length of the rectangle: 16 + 4 = 20m.
- Apply the formula: Area of rectangle = length x width.
- The increased area = new area of the rectangle - original area of the rectangle.
Answer
Initial area of the rectangle:
16 x 10 = 160 (m2)
Change in the area of the rectangle:
(16 + 4) x 10 = 200 (m2)
The increased area of the rectangle is:
200 - 160 = 40 (m2)
Answer: 40 m2
You are currently viewing guidance on solving Class 4 Math problems on pages 60 and 61 of VBT Workbook Volume 2, focusing on Exercise 136. You can revisit the solution for math problems on pages 58 and 59 of Workbook 2 for additional practice, or preview the solution for math problems on pages 61 and 62 of Workbook 2 Introduction to Ratios to gain further understanding of the lesson.
Wishing you all the best in learning mathematics.
