Guidelines for Solving Exercise 1 on Pages 123, 124 of Math Textbook Grade 4
Problem Statement: Find the suitable digit to fill in the asterisk for: a) 75... divisible by 2 but not divisible by 5. c) 75... divisible by 2 and divisible by 5. Is the number found divisible by 3? c) 75... divisible by 9 Is the number found divisible by 2 and 3?
To solve: - A number divisible by 5 has a units digit of 0 or 5. - A number divisible by both 2 and 5 has a units digit of 0. - A number divisible by 3 has a digit sum divisible by 3. - A number divisible by 9 has a digit sum divisible by 9. - A number divisible by both 2 and 3 must satisfy: Digit sum divisible by 3 and units digit is 0, 2, 4, 6, or 8.
Answers: a) Fill in the blank with one of these digits: 2, 4, 6, 8, hence: 752, 754, 756, 758. b) For a number divisible by 2 and 5, the units digit must be 0. So, fill in the blank with 0: 750. We have: 7 + 5 + 0 = 12; 12 is divisible by 3. So, 750 is divisible by 3. c) For a number 75... divisible by 9, 7 + 5 + ... must be divisible by 9, or 12 + ... must be divisible by 9. Fill in the blank with 6: 756. The units digit of 756 is 6, hence divisible by 2, and the digit sum is 18, divisible by 3. So, 756 is divisible by both 2 and 3.
Mytour just guided through solving exercise 1 on page 123, 124 of the Math 4 textbook. Additionally, we have exercises: Solve Exercise 2 on page 123, 124 of Math 4 textbook, Solve Exercise 3 on page 123, 124 of Math 4 textbook, Solve Exercise 4 on page 123, 124 of Math 4 textbook, and Solve Exercise 5 on page 123, 124 of Math 4 textbook, all with suggested methods. Check out the solution for class 4 math page 123, 124 to excel in 4th-grade math!
