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Guidance on solving exercise 2 page 22 Math 5 Textbook
Problem statement:
Calculate the perimeter of a rectangular piece of land, where the length is twice the width and 15m more than the width.
Solution method:
* Solving the problem using difference - ratio method:
- Summarize the problem with a line segment diagram (ensuring equal line segments)
- Find the difference of equal parts according to the diagram
- Find the smaller number (width) by dividing the difference and then multiplying by the number of parts of the smaller number
- Find the larger number (length) by multiplying the width by 2 (since the length is twice the width)
* Formula for calculating the perimeter of a rectangle: P = (a + b) x 2.
Answer:
We have the diagram:
According to the diagram, the difference of equal parts is:
2 - 1 = 1 (part)
The width of the land plot is
15 : 1 x 1 = 15 (m)
The length of the land plot is:
15 x 2 = 30 (m)
The perimeter of the land plot is:
(30 + 15) x 2 = 90 (m)
Answer: 90 m.
Here is the solution guide for exercise 2 page 22 Math 5 textbook. Additionally, there are 3 more exercises: Solve Exercise 1 Page 22 Math 5 Textbook, Solve Exercise 3 Page 22 Math 5 Textbook, and Solve Exercise 4 Page 22 Math 5 Textbook. Let's check out the solution guide for page 22 Math 5 Textbook to study Math Grade 5 well.
