Solving Exercise 3 on Page 100 in Math 5 Workbook

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Ngày cập nhật gần nhất: 15/4/2026

Solving Exercise 3 on Page 100 in Math 5 Workbook: Calculating the area of a circular table with a radius of 45cm.

Guidance on Solving Exercise 3 on Page 100 in Math 5 Workbook

Problem:
Calculate the area of a circular table with a radius of 45cm.

Solution Method:
- Apply the formula for calculating the area of a circle when the radius (r) is known: A = r x r x 3.14 or A = r² x 3.14 (Value of pi = 3.14)
- Substitute the corresponding values into the formula, calculate carefully to find the most accurate result.

Answer:
The area of the table surface is:
45 x 45 x 3.14 = 6358.5 (cm²)
6358.5 cm² = 63.585 dm²
Answer: 63.585 dm²

Mytour has just provided a solution for Exercise 3 on page 100 in Math 5 Workbook. Additionally, there are exercises Solving Exercise 1 on Page 100 in Math 5 Workbook and Solving Exercise 2 on Page 100 in Math 5 Workbook. We also recommend solving them using the same method. Check out the guidance on Solving Math 5 page 100 to excel in 5th-grade math.

Frequently Asked Questions

What formula is used to calculate the area of a circle?

The formula used to calculate the area of a circle is A = r² x π, where r is the radius and π (pi) is approximately 3.14. This helps in determining the area based on the radius provided.

How do you find the area of a circular table with a radius of 45 cm?

To find the area of a circular table with a radius of 45 cm, apply the formula A = r² x 3.14. Substitute 45 for r, resulting in an area of 6358.5 cm² or 685 dm².

Is it important to substitute values accurately in area calculations?

Yes, accurately substituting values in area calculations is crucial, as even small errors can lead to incorrect results, affecting subsequent calculations and understanding of the problem.

What is the area of a circular table with a radius of 45 cm?

The area of a circular table with a radius of 45 cm is 6358.5 cm², which can also be expressed as 685 dm². This indicates the size of the table's surface.

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