Solving Exercise 3 on Pages 124, 125 of 4th-grade Math Textbook

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Ngày cập nhật gần nhất: 1/5/2026

Solving Exercise 3 on Pages 124, 125 of 4th-grade Math Textbook: Concentrated Practice. a) Explain why the line segments AN and MC are parallel and equal.

Guidance for solving Exercise 3 on Pages 124, 125 of 4th-grade Math Textbook

Solution method:
Observe the illustration above carefully to answer the questions correctly.
- Formula for the area of a rectangle: S = a x b (where S is the area symbol; a is the length; b is the width)
- Formula for the area of a parallelogram: S = a x h (where S is the area symbol; a is the length of the base; h is the height).

Answer:

a) The line segments AN and MC represent opposite edges of the parallelogram AMCN, making them parallel and equal.

b) The area of the rectangle ABCD is:

12 x 5 = 60 (cm²)

Since N is the midpoint of side DC, the length of segment NC is:

12 : 2 = 6 (cm)

The parallelogram AMCN has a height MN equal to the width of the rectangle, so MN = 5cm.

The area of the parallelogram AMCN is:

6 x 5 = 30 (cm²)

We find: 60 : 30 = 2 (times)
So, the area of the rectangle ABCD is 2 times the area of the parallelogram AMCN.

Mytour has just provided guidance on solving exercise 3 on pages 124 and 125 of the 4th-grade math textbook. In addition, we also suggest solutions for Exercise 1 on Pages 124, 125 of the 4th-grade Math Textbook and Exercise 2 on Pages 124, 125 of the 4th-grade Math Textbook. Check out the instructions on solving 4th-grade math problems on pages 124, 125 to excel in the subject!

Frequently Asked Questions

What are the key characteristics of line segments AN and MC in Exercise 3?

Line segments AN and MC are parallel and equal because they are opposite edges of the parallelogram AMCN. This relationship is defined by the properties of parallelograms, where opposite sides are always parallel and of equal length.

How do you calculate the area of the rectangle ABCD mentioned in the blog?

To calculate the area of rectangle ABCD, use the formula S = a x b. Given the dimensions of length 12 cm and width 5 cm, the area is calculated as 12 x 5 = 60 cm².

What is the significance of the area comparison between rectangle ABCD and parallelogram AMCN?

The area comparison shows that the area of rectangle ABCD is twice that of parallelogram AMCN. This is determined by the calculated areas: rectangle ABCD has an area of 60 cm², while parallelogram AMCN has an area of 30 cm², resulting in a ratio of 60:30, or 2 times.

What guidance is provided for solving Exercise 3 in the 4th-grade math textbook?

The guidance emphasizes careful observation of the illustration and provides essential formulas for calculating the areas of rectangles and parallelograms. This structured approach aids students in understanding and correctly solving the exercise.

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