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Guidance for solving Exercise 4 on page 26 of Math Grade 4
Problem:
In the 60m race. Nam finishes in 1/4 minute, Binh finishes in 1/5 minute. Who runs faster and by how many seconds?
Solution Method:
* Observations:
- The problem states:
+ Nam finishes in 1/4 minute
+ Binh finishes in 1/5 minute.
- The problem requires:
+ Identify the faster runner between the two
+ Determine how many seconds faster that person is?
* Steps:
- Convert time units: Minutes to seconds
- After converting to the same unit (seconds), compare the two numbers to find the fastest runner (note: the fastest runner has the least number of seconds).
- To determine how many seconds faster: Subtract the smaller number of seconds from the larger one.
Answer:
Conversion: 1/4 minute = 15 seconds, 1/5 minute = 12 seconds.
It can be seen that 12 seconds is less than 15 seconds => Binh runs faster than Nam by: 15 - 12 = 3 seconds.
Mytour has just provided a solution for Exercise 4 on Page 26 of Math Grade 4. Additionally, we have solutions for Exercise 1 on Page 26 of Math Grade 4, Exercise 2 on Page 26 of Math Grade 4, Exercise 3 on Page 26 of Math Grade 4, and Exercise 5 on Page 26 of Math Grade 4. All come with our suggested methods. Let's explore the guidance on solving exercises on page 26 of math grade 4 to excel in 4th-grade math.
