Solution to Exercise 1 on Page 153 of Math 3 Textbook
Problem Statement:
Calculate the area and perimeter of a rectangle with a length of 4 dm and a width of 8 cm.
Answer:
Convert: 4 dm = 40 cm
The area of the rectangle is:
320 multiplied by 8 equals 320 (cm2)
The perimeter of the rectangle is:
(40 plus 8) multiplied by 2 equals 96 (cm)
Answer: 320 cm2; 96 cm
Solution to Exercise 2 on Page 153 of Math 3 Textbook
Problem Statement:
Figure H consists of rectangle ABCD and rectangle DMNP (with dimensions indicated on the diagram)
a) Calculate the area of each rectangle in the diagram
b) Calculate the area of figure H.
Answer:
a) The area of rectangle ABCD is:
8 multiplied by 10 equals 80 (cm2)
The area of rectangle DMNP is:
20 multiplied by 8 equals 160 (cm2)
b) The area of figure H is:
80 plus 160 equals 240 (cm2)
Solution to Exercise 3 on Page 153 of Math 3 Textbook
Problem Statement:
A rectangle has a width of 5cm, and its length is twice its width. Calculate the area of this rectangle.
Answer:
The length of the rectangle is:
5 multiplied by 2 equals 10 (cm2)
The area of the rectangle is:
10 multiplied by 5 equals 50 (cm2)
The answer is: 50 square centimeters.
Mastering the knowledge of square area with detailed solutions provided in Exercise Solutions on pages 153, 154 of Math 3 textbook as well as the practice exercises on page 154 of Math 3 textbook with the following Solution to Exercise on page 154 of Math 3 textbook.
Detailed content of the Solution to Exercise on page 60 of Math 3 textbook has been thoroughly explained for your reference and preparation to enhance your understanding of Math 3 subject.
In addition to the content covered, you can prepare and explore the Solution to Exercise on page 59 of Math 3 textbook to grasp the concepts outlined in the Math 3 curriculum.
