Solving exercises on page 154 of Math 2 textbook

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Ngày cập nhật gần nhất: 15/4/2026

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Solution to exercise 1 on page 154 of Math 2 textbook

Solution to exercise 2 on page 154 of Math 2 textbook

Solution to exercise 3 on page 154 of Math 2 textbook

Solution to exercise 4 on page 154 of Math 2 textbook

All exercises in the solving exercises section on page 154 of Math 2 textbook aim to help students reinforce their understanding of length units they have learned: Meter, kilometer, millimeter... through various exercises involving evaluating expressions, solving word problems, and multiple-choice exercises.

Solution to exercise 1 on page 154 of Math 2 textbook

Problem statement:

Calculate:

13 meters plus 15 meters equals 5 kilometers times 2 =

66 kilometers minus 24 kilometers equals 18 meters divided by 3 =

23 millimeters plus 42 millimeters equals 25 millimeters divided by 5 =

Answer:

13 meters + 15 meters = 18 meters, 5 kilometers times 2 = 10 kilometers

66 kilometers minus 24 kilometers = 42 kilometers, 18 meters divided by 3 = 6 meters

23 millimeters plus 42 millimeters = 65 millimeters, 25 millimeters divided by 5 = 5 millimeters

Solution to exercise 2 on page 154 of Math 2 textbook

Problem statement:

A person travels 18 kilometers to reach the town, then travels an additional 12 kilometers to reach the city. How many kilometers has the person traveled in total?

The total distance traveled by the person is:

18 plus 12 equals 30 (kilometers)

Answer: 30 kilometers

Solution to exercise 3 on page 154 of Math 2 textbook

Problem statement:

Circle the letter of the correct answer:

A tailor uses 15 meters of fabric to make 5 identical sets of clothes. How many meters of fabric are needed to make one set of clothes like that?

A. 10 meters

B. 20 meters

C. 3 meters

Answer:

Circle the letter C.

Solution to exercise 4 on page 154 of Math 2 textbook

Problem statement:

Measure the lengths of the sides of triangle ABC and then calculate the perimeter of the triangle.

Measuring the lengths of the sides of triangle ABC, we get:

AB = 3 centimeters, AC = 4 centimeters, BC = 5 centimeters.

Perimeter of triangle ABC is:

3 + 4 + 5 = 12 (cm)

Answer: 12 cm

Above is the complete hint for Solving exercises on page 154 of Math 2 textbook. Prepare the content of the Article number as the sum of hundreds, tens, units with the part Solving exercises on page 155 of Math 2 textbook and the Addition (not remembered) within the scope of 1000 through the content Solving exercises on page 156 of Math 2 textbook to study Math 2 better.

Frequently Asked Questions

What are the main goals of the exercises on page 154 of the Math 2 textbook?

The main goals of the exercises on page 154 of the Math 2 textbook are to help students reinforce their understanding of length units, including meters, kilometers, and millimeters, through various problem-solving methods.

How can students effectively calculate total distance traveled in Math 2 exercises?

Students can effectively calculate total distance traveled by adding the distances of each segment together, as demonstrated in the example where a person traveled 18 kilometers plus an additional 12 kilometers, resulting in a total of 30 kilometers.

What is the method to find the perimeter of triangle ABC?

To find the perimeter of triangle ABC, measure the lengths of each side, which are AB = 3 cm, AC = 4 cm, and BC = 5 cm, and then sum these values to get the perimeter: 3 + 4 + 5 = 12 cm.

What types of problems are included in the Math 2 exercises on page 154?

The Math 2 exercises on page 154 include evaluating expressions, solving word problems involving distance, and multiple-choice questions related to fabric measurement, all designed to enhance students' understanding of mathematical concepts.

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