Solving exercise 1 on page 163 of the Math 3 textbook
Exercise:
Calculate:
Answer:
Solving exercise 2 on page 163 of the Math 3 textbook
Exercise:
Answer:
The amount of cement sold is:
36550 ÷ 5 = 7310 (kg)
The remaining amount of cement is:
36550 minus 7310 equals 29240 (kg)
Solving exercise 3 on page 163 of the Math 3 textbook
Exercise:
Calculate the value of the expression:
a) 69218 minus 26736 divided by 3
30507 plus 27876 divided by 3
b) the sum of 35281 and 51645 divided by 2
the result of 45405 minus 8221 divided by 4
Answer:
69218 minus 26736 divided by 3 equals 69218 minus 8912 equals 60306
30507 plus 27876 divided by 3 equals 30507 plus 9292 equals 39799
the sum of 35281 and 51645 divided by 2 equals 86926 divided by 2 equals 43463
the result of 45405 minus 8221 divided by 4 equals 37184 divided by 4 equals 9296
Solving exercise 4 on page 163 of the Math 3 textbook
Exercise:
Given 8 triangles as follows. Arrange them into the shape below:
Answer:
In addition to the above content, you can explore exercises on page 42 of the Math 3 textbook to enhance your knowledge of Math 3.
Alongside the learned content, you can prepare and delve into exercises on page 43 of the Math 3 textbook to solidify your understanding of the Math 3 curriculum.
Following the division of five-digit numbers by single-digit numbers with the solution for exercises on page 163 of the Math 3 textbook, the subsequent content will include solutions for exercises on page 164 and the Practice section on page 165 of the Math 3 textbook to further your understanding of Math 3.
