Solving exercises on page 172 of Math 5 Textbook, Practice Session

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Solving exercises on page 172 of Math 5 Textbook, Practice Session

The next review topics in solving exercises on page 172 of Math 5 Textbook are perimeter of rectangle, area of rectangle, area of trapezoid, area of triangle. To solve these exercises, students not only need to memorize formulas but also apply them flexibly and effectively.

Solving exercises on page 172 of Math 5 Textbook, Practice Session

Exercise 1 Math 5 Page 172 SGK
Problem:
A rectangular foundation has a length of 8m, and a width equal to 3/4 of the length. Square bricks with a side length of 4dm are used to pave the foundation. The price for each brick is 20,000 VND. How much money is needed to pave the entire foundation? (Ignore the cost of mortar).

Solution Method:

- Calculate the width of the foundation = length × 3/4.

- Calculate the area of the foundation = length × width.

- Calculate the area of one square brick = side length × side length.

- Calculate the number of bricks needed = area of foundation : area of one square brick.

- Cost of buying bricks = price per brick × number of bricks needed.

Solution:

Exercise 2 Math 5 Page 172 SGK
Problem:
A trapezoidal field has an average of two bases equal to 36m. The area of that field is equal to the area of a square plot with a perimeter of 96m.
a) Calculate the height of the trapezoidal field.
b) Given the difference between two bases is 10m, calculate the length of each base of the trapezoidal field.

Solution Method:

- Calculate the length of one side of the square plot = perimeter : 4.

- Calculate the area of the trapezoidal field (also the area of the square plot) = side length × side length.

- Calculate the height of the trapezoidal field = area × 2 : average of two bases.

- Sum of the lengths of two bases = average of two base lengths × 2.

- Find the lengths of two bases using the problem of finding two numbers given their sum and difference:

Larger number = (Sum + Difference) : 2.

Smaller number = (Sum – Difference) : 2.

Solution:
a) The side length of the square plot is:
96 : 4 = 24 (m)
The area of the square plot is:
24 x 24 = 576 (m²)
So, the area of the trapezoidal field is 576m².
The height of the trapezoidal field is:
576 : 36 = 16 (m)
b) The total length of the two bases of the trapezoidal field is: 36 x 2 = 72 (m)
We have the diagram:

After the lesson on square meters, we continue practicing on this lesson, the hints to solve problem 5 on pages 28-29 will help students grasp the knowledge better.

Solution Method:

To solve the problem, students need to use the following formulas:

- Rectangle perimeter = (length + width) × 2.

- Triangle area = base length × height : 2.
- Trapezoid area = (large base + small base) × height : 2.

Solution:

Here is the hint for Solving exercises on page 172 of Math 5 textbook with complete details. Students prepare for the content of Reviewing charts through Solving exercises on pages 173, 174, 175 of Math 5 textbook and the Concentrated Practice Exercise on page 175 of Math 5 textbook through Solving exercises on page 175 of Math 5 textbook to study Math 5 better.

In the Grade 5 math curriculum, Solving exercises on page 45 of Math 5 textbook is one of the crucial topics that students need to focus on and improve to enhance their math-solving skills.

Detailed instructions for solving exercises on page 44 of Math 5 textbook have been provided for students to refer to and prepare for better practice in Grade 5 math.

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