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Solving exercises on page 55 of Math textbook Grade 5, Concentrated practice - Including solving methods
Solution for Exercise 1 on page 55 of Math textbook Grade 5
Problem:
Calculate:
a) 605.26 + 217.34; b) 800.56 - 384.48; c) 16.39 + 5.25 - 10.3.
Solution:
Students should write down the calculations on rough paper and then fill in the answers.
a) Refer to the method of adding two decimal numbers in the section Solution for Exercise 1 on page 50 of Math textbook Grade 5.
b) Refer to the method of subtracting two decimal numbers in the section Solution for Exercise 1 on page 54 of Math textbook Grade 5.
c) Students perform calculations from left to right.
Answer:
a) 605.26 + 217.34 = 822.60
b) 800.56 - 284.48= 416.08
c)
Method 1: 16.39 + 5.25 - 10.3 = 21.64 - 10.3 = 11.34
Method 2: 16.39 + 5.25 - 10.3 = 16.39 - 10.3 + 5.25 = 6.09 + 5.25 = 11.34
Solution for Exercise 2 on page 55 of Math textbook Grade 5
Problem:
Find x:
a) x - 5.2 = 1.9 + 3.8
b) x + 2.7 = 8.7 + 4.9
Solution:
- Step 1: Calculate the sum on the right side
- Step 2:
a) Hide x as the number to be subtracted, so to find the subtracted number, we add the difference to the subtracted number
b) Hide x as the term, so to find the unknown term, we subtract the sum from the known term.
Answer:
a) x - 5.2 = 1.9 + 3.8
x - 5.2 = 5.7
x = 5.7 + 5.2
x = 10.9
b) x + 2.7 = 8.7 + 4.9
x + 2.7 = 13.6
x = 13.6 - 2.7
x = 10.9.
Solution for Exercise 3 on page 55 of Math textbook Grade 5
Problem:
Calculate in the most convenient way:
a) 12.45 + 6.98 + 7.55;
b) 42.37 - 28.73 - 11.27.
Solution:
Students apply the associative property of addition, grouping numbers so that when added together, they result in a whole number, then add the remaining number.
Answer:
a) 12.45 + 6.98 + 7.55
= (12.45 + 7.55) + 6.98
= 20 + 6.98
= 26.98
b) 42.37 - 28.73 - 11.27
= 42.37 - (28.73 + 11.27)
= 42.37 - 40
= 2.37.
Solution for Exercise 4 on page 55 of Math textbook Grade 5
Problem:
A person rides a bike for three hours and covers 36km. In the first hour, the person travels 13.25km, in the second hour, the person travels 1.5km less than in the first hour. How many kilometers does the person travel in the third hour?
Solution:
- Step 1: Find the number of kilometers the person travels in the second hour by subtracting the number of kilometers traveled in the first hour from the number of kilometers traveled less than the first hour.
- Step 2: Calculate the total kilometers covered in the first two hours by adding the number of kilometers traveled in the first hour to the number of kilometers traveled in the second hour.
- Step 3: Find the number of kilometers the person travels in the third hour by subtracting the total kilometers traveled in three hours (given in the problem) from the number of kilometers traveled in the first two hours.
Answer:
The person travels in the second hour:
13.25 - 1.5 = 11.75 (km)
The person travels in the first two hours:
13.25 + 11.75 = 25 (km)
The person travels in the third hour:
36 - 25 = 11 (km)
Answer: 11 km.
Solution for Exercise 5 on page 55 of Math textbook Grade 5
Problem:
The sum of three numbers is 8. The sum of the first and second numbers is 4.7. The sum of the second and third numbers is 5.5. Find each number.
Solution:
- Find the first number by: Subtracting the sum of three numbers from the sum of the first and second numbers.
- Find the second number by: Subtracting the first number from the sum of the first and second numbers.
- Find the third number by: Subtracting the second number from the sum of the second and third numbers.
Answer:
The first number is: 8 - 5.5 = 2.5
The second number is: 4.7 - 2.5 = 2.2
The third number is: 8 - 4.7 = 3.3
Answer: 2.5; 2.2; 3.3.
Solving Exercise on page 55 of Math textbook Grade 5, Concentrated practice - Concise
Solution for Exercise 1 on page 55 of Math textbook Grade 5, Concentrated practice
a) 605.26 + 217.34;
b) 800.56 – 284.48;
c) 16.39 + 5.25- 10.3.
Answer:
a) 605.26 + 217.34 = 822.60
b) 800.56 – 284.48= 416.08
c)
Method 1: 16.39 + 5.25 – 10.3 = 21.64 – 10.3 = 11.34
Method 2: 16.39 + 5.25 – 10.3 = 16.39 – 10.3 + 5.25 = 6.09 + 5.25 = 11.34
Solution for Exercise 2 on page 55 of Math textbook Grade 5, Concentrated practice
a) x – 5.2 = 1.9 + 3.8
b) x + 2.7 = 8.7 + 4.9
Answer:
a) x – 5.2 = 1.9 + 3.8
x – 5.2 = 5.7
x = 5.7 + 5.2
x = 10.9
b) x + 2.7 = 8.7 + 4.9
x + 2.7 = 13.6
x = 13.6 – 2.7
x = 10.9
Solution for Exercise 3 on page 55 of Math textbook Grade 5, Concentrated practice
Calculate in the most convenient way:
a) 12.45 + 6.98 + 7.55;
b) 42.37 – 28.73 – 11.27.
Answer :
a) 12.45 + 6.98 + 7.55 = 12.45 + 7.55 = 6.98
= 20 + 6.98
= 26.98
b) 42.37 – 28.73 – 11.27 = 42.37 – (28.73 + 11.27)
= 42.37 – 40
= 2.37.
In Chapter I, we acquaint ourselves with units of measurement, where Hectare is extensively used. Let's take a look at hints for Solving Math 5 on pages 29, 30 to study Math Grade 5 well.
Solution for Exercise 4 on page 55 of Math textbook Grade 5, Concentrated practice
A person rides a bike for three hours and covers 36km. In the first hour, the person travels 13.25km, in the second hour, the person travels 1.5km less than the first hour. How many kilometers does the person travel in the third hour?
Summary:
The person travels in the second hour:
13.25 – 1.5 = 11.75 (km)
The person travels in the first two hours:
13.25 + 11.75 = 25 (km)
The person travels in the third hour:
36- 25 = 11 (km)
Answer: 11 km
Solution for Exercise 5 on page 55 of Math textbook Grade 5, Concentrated practice
The sum of three numbers is 8. The sum of the first and second numbers is 4.7. The sum of the second and third numbers is 5.5. Find each number.
Summary:
The first number is: 8 – 5.5 = 2.5
The second number is: 4.7 – 2.5 = 2.2
The third number is: 8 – 4.7 = 3.3
Answer: 2.5; 2.2; 3.3.
Above is the hint for Solving Exercise on page 55 of Math textbook Grade 5 with full details. Prepare for the content of Multiplying a decimal by a natural number through Solving Exercise on page 56 of Math textbook Grade 5 and Multiplying a decimal by 10, 100, 1000,.. through Solving Exercise on page 57 of Math textbook Grade 5 to study Math Grade 5 better.
In addition to the learned content, you can prepare and understand the content of Solving Exercise on page 60 of Math textbook Grade 5 or solving Math Grade 5 on page 70 to master the knowledge in the Grade 5 Math curriculum.
In the Grade 5 Math curriculum, Solving Exercise on page 61 of Math textbook Grade 5 is one of the very important contents that students need to pay attention to and improve to enhance their Math 5 solving skills.
