Buzz
Given a) 278157 : 3 = 92719 and b) 158735 : 3 = 52911
To divide a number with multiple digits by a single-digit number: - Arrange the division vertically - Divide each digit of the dividend by the divisor (if the first digit of the dividend is smaller than the divisor, take two digits), get the quotient, multiply it by the divisor, subtract the result from the first two digits of the dividend - Bring down the next digit of the dividend, divide it by the divisor, get the quotient, repeat the process until the division is complete - The result may be a whole number or have a remainder.
Solve question 2 on page 77 of the Math 5 textbook.
128610 liters of petrol are evenly distributed into 6 tanks. How many liters of petrol are in each tank?
To find the amount of petrol in each tank, divide the total amount of petrol by 6. 128610 ÷ 6 = 21435 liters.
The amount of petrol in each tank is: 128610 ÷ 6 = 21435 (liters). Answer: 21435 liters of petrol.
Solve question 3 on page 77 of the Math 5 textbook.
Perform the operation: 187250 ÷ 8. The quotient is the number of boxes that can be arranged, the remainder is the number of spare shirts.
Step 1: Perform the division as usual, following the instructions in the solution to question 1 on page 77 of the Math 4 textbook. Step 2: Conclusion: In the result of the division, the quotient is the maximum number of boxes that can be arranged, and the remainder is the number of spare shirts.
Upon performing the division, we get: 187250 ÷ 8 = 23406 (remainder 2). So, the maximum number of boxes that can be arranged is 23406, with 2 shirts remaining. Answer: 23406 boxes and 2 shirts remaining.
Solve exercise 1 on page 77 of the Math 4 textbook.
Task:
Perform the following divisions:
a) 278 157 ÷ 3
304 968 ÷ 4
408 090 ÷ 5
b) 158 735 ÷ 3
475 908 ÷ 5
301 849 ÷ 7
Answer:
Solve exercise 2 on page 77 of the Math 4 textbook
Task:
128 610 liters of petrol are evenly distributed into 6 tanks. How many liters of petrol are in each tank?
Response:
The amount of petrol in each tank is:
128 610 ÷ 6 = 21 435 (liters)
Answer: 21 435 (liters)
Solve exercise 3 on page 77 of the Math 4 textbook
Task:
187 250 shirts are arranged into boxes, with 8 shirts in each box. How many boxes can be arranged at most and how many shirts are left over?
Response:
We have: 187 250 ÷ 8 = 23 406 (remainder 2)
So, we can arrange at most 23 406 boxes and have 2 shirts left over
Answer: 23 406 boxes and 2 shirts left over
Chapter II Division in grade 4, students will practice Exercise 78 in Math 4 textbook along with solving Exercise 4 on page 78.
The next lesson in Chapter II Division for grade 11 focuses on dividing two numbers ending in 0. Students should also refer to the hints for solving Exercise 4 on page 80 in Math 4 textbook to reinforce their understanding and excel in Math 4.
Detailed solutions for Exercise 4 on pages 67 and 68 have been thoroughly provided for students to consult and prepare in order to improve their proficiency in Math 4.
In addition to the covered material, students can prepare and explore the solutions for Exercise 4 on page 65 to solidify their grasp of the concepts in the Math 4 curriculum.
