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Solving Math Grade 3 exercises on pages 113 and 114 of Cánh Diều Book Volume 2
Comprehensive review of solving exercises on pages 113 and 114 of Math 3 Workbook Volume 2, Cánh Diều Book
Focus Review
1. Solve Exercise 1 Page 113 Math Grade 3 Textbook
Problem: a) Number ?
b) Round the number 62,000 to the nearest ten thousand.
c) Arrange the following numbers in ascending order: 15,896; 15,968; 15,986; 15,698
Solution Guide:
a) Observe the number line, determine the distance between two marks to fill in the appropriate number in the blank space.
b) Use the method of rounding to the nearest ten thousand to answer the question.
Answer:
2. Solve Exercise 2 Page 113 Math Grade 3 Textbook
Problem: Set up the calculation and then solve it.
Solution Guide:
For addition and subtraction:
- Write the calculation vertically so that the numbers in the same column are aligned.
- Perform addition and subtraction step by step from right to left.
For multiplication and division:
- Set up the multiplication and division.
- For multiplication: Multiply in order from right to left.
For division: Divide step by step from left to right.
Answer:
3. Solve Exercise 3 Page 113 Math Grade 3 Textbook
Problem: Below is a table of statistics on the quantity of eucalyptus oil sold by a store in the last three months of the year.
Based on the table, answer the following questions:
a) In November, the store sold 2,250 ml of tea tree oil.
b) In which month did the store sell the most tea tree oil? December.
c) Over the three months, the store sold a total of:
3,200 + 2,250 + 4,800 = 10,250 (ml)
Solution Guide: Read the data table to answer the questions.
Answer:
a) In November, the store sold 2,250 ml of tea tree oil.
b) In December, the store sold the most tea tree oil.
c) Over the three months, the store sold a total of:
3,200 + 2,250 + 4,800 = 10,250 (ml)
4. Solve Exercise 4 Page 114 Math Grade 3 Textbook
a) Identify the center and radius of each circle below:
b) Read the name of the midpoint of segment BC in the figure.
Solution Guide: Observe the diagram to answer the questions.
Answer:
a) Circle with center O, radius OD, OC.
Circle with center A, radius Replaced by the image below.
b) Point O is the midpoint of segment BC (because point O is between points B, C, and OB = OC).
5. Solve Exercise 5 Page 114 Math Grade 3 Textbook
Problem: Observe the pictures and choose the correct statement.
a) The area of shape B is twice the area of shape A.
b) The area of shape C is four times the area of shape A.
c) The perimeter of shape B is twice the perimeter of shape A.
d) The perimeter of shape C is five times the perimeter of shape A.
Solving Strategy:
Count the number of squares to determine the area of each shape.
Compare the perimeters and areas of the shapes and draw conclusions.
Answer:
+ Each square has an area of 1 cm2.
The area of shape A consists of 4 squares. Therefore, the area of shape A is 4 cm2.
The area of shape B consists of 8 squares. Therefore, the area of shape B is 8 cm2.
The area of shape C consists of 20 squares. Therefore, the area of shape C is 20 cm2.
Thus, the area of shape B is twice the area of shape A, and the area of shape C is five times the area of shape A. So, a) true, b) false.
+ Square A has a side length of 2 cm, so its perimeter is: 2 x 4 = 8 (cm)
Rectangle B has a length of 4 cm and a width of 2 cm, so its perimeter is:
(4 + 2) x 2 = 16 (cm)
Rectangle C has a length of 5 cm and a width of 4 cm, so its perimeter is:
(5 + 4) x 2 = 18 (cm)
Thus, the perimeter of shape B is twice the perimeter of shape A. So, c) true, d) false.
6. Solve Exercise 6 Page 114 Math Grade 3 Textbook
Problem: According to you, how many grams does each scale below weigh? Knowing that the weights of the scales are equal.
Guidelines: When the scales are balanced, the mass on both sides of the scale is equal. From there, find the mass of each weight.
Answer:
Convert 1 kg 500 g to 1,500 g.
Observing the illustration, we see that the scales are balanced. Therefore, the total mass of the 4 weights equals the sum of the pumpkin and one weight. Since the weights have equal weights, the mass of the pumpkin equals the mass of 3 weights.
So, the mass of one weight is: 1,500 : 3 = 500 (g)
Solving Strategy: When the scale is balanced, the mass on both sides is equal. Therefore, find the mass of each weight.
Answer:
Convert 1 kg 500 g to 1,500 g.
Observing the illustration, we see that the scales are balanced. Therefore, the total mass of the 4 weights equals the sum of the pumpkin and one weight. Since the weights have equal weights, the mass of the pumpkin equals the mass of 3 weights.
So, the mass of one weight is: 1,500 : 3 = 500 (g)
We hope that solving exercises on pages 113 and 114 of the Math Grade 3 Textbook, Cánh Diều series, will be a useful reference for 3rd-grade students to effectively learn and reinforce the concentrated review lesson.
