Solving exercises on pages 16 and 17 of Math 5 textbook

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Guidance on solving exercises on pages 16 and 17 of Math 5 textbook including solution methods

1. Solve problem 1 on Page 16, 17 of Math 5 textbook

Problem statement:

Calculate:

Solution method:

- Convert mixed numbers to fractions (as instructed in problem 1 on page 14)

- Perform multiplication and division operations:

+ To multiply two fractions, multiply the numerator of the first fraction by the numerator of the second fraction and the denominator of the first fraction by the denominator of the second fraction

+ To divide two fractions, invert the second fraction (numerator becomes denominator and denominator becomes numerator), then change the division sign to multiplication and perform multiplication of the two fractions

Answer:

2. Solve problem 2 on Page 16, 17 SGK Mathematics 5

Problem statement:

Find x:

Solution method:

Determine the role of x in the operation then perform according to the learned rules:

- To find the unknown term, subtract the known term from the total.

- To find the subtracted term, add with the subtracting term.

- To find the unknown factor, divide the product by the known factor.

- To find the dividend, multiply with the divisor to get the quotient.

Answer:

3. Solve problem 3 on Page 16, 17 of Math 5 textbook

Problem statement:

Write the length measurements (following the pattern):

Solution method:

- Convert all measurements to the same unit and then perform addition operation

+ 1m equals 100cm or 1cm equals 1/100m

Problem statement:

4. Solve problem 4 on Page 16, 17 of Math 5 textbook

Problem statement:

Circle the letter preceding the correct answer:

A rectangular piece of land with dimensions as shown in the diagram below.

After digging a pond and building a house, the remaining land area is:

A. 180 m²                                   B. 1400 m²

C. 1800 m²                                   D. 2000 m²

Solution method: 

+ The width of the land is divided into 4 equal parts, each part being 10m, so the length is 10 x 4 =40m

+ The length of the land is divided into 5 equal parts, each part being 10m, so the length is 10 x 5 =50m

+ The width of the house is 10m (as it is one part)

+ The length of the house is divided into 2 equal parts, each part being 10m, so the length is 10 x 2 =20m

+ The length and width of the pond are both 20m

Calculate the area of the land, house, and pond: Multiply the length by the width

The area of the remaining land will be equal to the area of the land minus the area of the house and the area of the pond

Answer:

The length of the land is 50m. The width of the land is 40m. The area of the land is: 50 x 40 = 2000 m²

- The length of the house is 20m. The width of the house is 10m. The area of the house is: 20 x 10 = 200 m²

- The square pond has a long side of 20m. The area of the pond is: 20 x 20 = 400 m²

- The area of the remaining land is: 2000 - (200 + 400) = 1400 m²

=> B is the correct answer

Concise guide to solving exercises on pages 16 and 17 of Math 5 textbook

Solve Exercise 1 on pages 16 and 17 of Math 5 textbook

Solution

Solve Exercise 2 on pages 16 and 17 of Math 5 textbook

Solution

Solve Exercise 3 on pages 16 and 17 of Math 5 textbook

Solution

Solve Exercise 4 on pages 16 and 17 of Math 5 textbook

Solution

Above is the solution to exercises 16, 17 in the Math 5 textbook. Students can review the solutions to exercises 15, 16 in the Math 5 textbook previously solved, or carefully review other solution sections to improve their Math 5 skills.

In the Math 5 curriculum, solving exercises on page 71 of the Math 5 textbook is one of the crucial topics that students need to focus on and enhance to improve their Math 5 skills.

In addition to the above content, students can explore the solution section for page 76 of the Math 5 textbook to enhance their knowledge of Math 5.