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Solving Math problems for 3rd grade on pages 39 and 40 in Volume 2 textbook
Addition within the range of 10,000
Adding within the scope of 10,000
Activity
1. Solve Exercise 1 Page 39 Mathematics Grade 3
Problem: Calculate.
Solution: Add numbers in the same place value from right to left.
Answer:
2. Solve Exercise 2 Page 39 Mathematics Grade 3
Problem: Set up the calculation and solve.
Solution Guide:
- Operation: Write the addition vertically so that the numbers in the same column align with each other.
- Calculation: Add the numbers from right to left.
Answer:
3. Solve Exercise 3 Page 39 Math Book Grade 3
Problem: This harvest season, Uncle Hung harvested 2,530 kg of rice, and Uncle Duong harvested 550 kg more rice than Uncle Hung. How much rice did Uncle Duong harvest this season?
Solution Approach: The amount of rice Uncle Duong harvested is equal to the amount Uncle Hung harvested plus 550 kg.
Answer:
Uncle Duong harvested the amount of rice:
2,530 + 550 = 3,080 (kg)
Result: 3,080 kg of rice.
Practice
1. Solve Exercise 1 Page 39 Math Book Grade 3
Problem: Perform mental calculations (following the example).
Solution Guide: Observe the example, then mentally calculate the addition of the rounded thousands.
Answer:
a) 6 thousand + 2 thousand = 8 thousand
6,000 + 2,000 = 8,000.
b) 3 thousand + 4 thousand = 7 thousand
3,000 + 4,000 = 7,000.
c) 5 thousand + 4 thousand = 9 thousand
5,000 + 4,000 = 9,000.
d) 1 thousand + 9 thousand = 10 thousand
1,000 + 9,000 = 10,000.
2. Solve Exercise 2 Page 40 Math Book Grade 3
Problem: Perform mental calculations (following the example).
Solution Guide: Observe the example, then mentally calculate the addition of the rounded hundreds.
Answer:
a) 3 hundred + 7 hundred = 9 hundred
3 thousand 2 hundred + 7 hundred = 3 thousand 9 hundred
3,200 + 700 = 3,900
b) 5 thousand + 5 hundred = 5 thousand 5 hundred
5,000 + 500 = 5,500
c) 6 hundred + 2 hundred = 8 hundred
8 thousand 6 hundred + 2 hundred = 8 thousand 8 hundred
8,600 + 200 = 8,800
d) 1 hundred + 8 hundred = 9 hundred
6 thousand 1 hundred + 8 hundred = 6 thousand 9 hundred
6,100 + 800 = 6,900
3. Solve Exercise 3 Page 40 Math Book Grade 3
Problem: Ants will visit the store with the largest calculation result. Which store will the ants go to?
Solution Guide: Calculate each operation at the stores. Compare the results to find the store with the largest calculation result.
Answer:
A. 5,800 + 2,000 = 7,800
B. 5,800 + 2,500 = 8,300
C. 5,800 + 2,200 = 8,000
- See more: Solve exercises on pages 41 and 42 of Math Book 3 Volume 2, the book Connecting Knowledge with Life
4. Solve Exercise 4 Page 40 Math Book Grade 3
Problem: In a football match, the number of spectators in stand A is 4,625 people. The number of spectators in stand B is 438 more than in stand A. How many spectators are there in both stands?
Solution Guide:
Step 1: Find the number of spectators in stand B = Number of spectators in stand A + 438 people.
Step 2: Find the number of spectators in both stands = Number of spectators in stand A + Number of spectators in stand B.
Answer:
The number of spectators in stand B is:
4,625 + 438 = 5,063 (people)
The number of spectators in both stands is
4,625 + 5,063 = 9,688 (people)
Result: 9,688 people
Solving exercises on pages 39 and 40 of Math Book 3 Volume 2, the book Connecting Knowledge with Life is a useful resource. Pay attention to easily complete exercises and grasp the knowledge effectively.
