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Solving exercises on pages 42 and 43 of Grade 3 Math Textbook Volume 1, Kite Book
Solutions for exercises on pages 42 and 43 of Grade 3 Math Textbook Volume 1, Kite Book
Division Table 6
1. Solve Exercise 1 on Page 42 of Grade 3 Math Textbook
Problem: Calculate:
a)
6 x 2 6 x 7 6 x 9
12 : 6 42 : 6 54 : 6
12 : 2 42 : 7 54 : 9
b) 24 g : 6 60 cm : 6 36 l : 6
Solution Guide:
a) In each column, we rely on the first multiplication to write the results of the two divisions below.
b) Perform division as usual, writing the corresponding units after the result.
Answers:
a)
6 x 2 = 12 6 x 7 = 42 6 x 9 = 54
12 : 6 = 2 42 : 6 = 7 54 : 6 = 9
12 : 2 = 6 42 : 7 = 6 54 : 9 = 6
b) 24 g : 6 = 4 g 60 cm : 6 = 10 cm 36 l : 6 = 9 l
2. Solve Exercise 2 on Page 42 of Grade 3 Math Textbook
Problem: Number ?.
Guidance: Quotient = Dividend : Divisor.
Answer:
- See also: Solution manual for exercises on page 45 of Grade 3 Math Textbook Volume 1, Kite Book
3. Solve Exercise 3 on Page 43 of Grade 3 Math Textbook
Problem: What is the number?
Answer:
4. Solve Exercise 4 on Page 43 of Grade 3 Math Textbook
Problem: Mr. Hung raises 48 pigeons in cages, with 6 pigeons in each cage. How many pigeon cages does Mr. Hung have?
Solution: Number of pigeon cages = Number of pigeons : number of pigeons per cage.
Answer:
Mr. Hung has the number of pigeon cages:
48 : 6 = 8 (cages)
Answer: 8 pigeon cages.
In addition to referring to the solution for exercises on pages 42 and 43 of Grade 3 Math Textbook Volume 1, Kite Book, students should remember to do extra exercises and review the theory to reinforce their knowledge further.
