Solving exercises on pages 56 and 57 of Math 3 Volume 2 textbook, the innovative book 'Horizon of Creativity'

Solving Math Grade 3, page 56, 57, book 'Horizon of Creativity' volume 2
 

Solving exercises on pages 56 and 57 of Math 3 Volume 2 textbook, the innovative book 'Horizon of Creativity.'

Comparing numbers with five digits

Practical Exercise

1. Solve Exercise 1 Page 56 Math Grade 3

Problem:

Solution Guide: Compare pairs of digits in the same row from left to right.

Answer:

2. Solve Exercise 2 Page 57 Math Grade 3

Problem: Given four numbers: 75,638; 73,856; 76,385; 78,635.
a) Arrange the numbers in descending order.
b) Find the position of each given number on the number line in the figure below.

Solution Guide:
a) Compare the given numbers and arrange them in descending order.
b) Apply the knowledge: On the number line, the number to the left is smaller than the one to the right; hence, fill in the appropriate numbers in each position.

Answer:

Practice

1. Solve Exercise 1 Page 57 Math Grade 3

Problem: Replace the letters with the symbol ?.

Solution Guide: Utilize the method of comparing two numbers to find the appropriate digit to fill in the blank space.

Answer:

2. Solve Exercise 2 Page 57 Math Grade 3

Problem: Determine which statement is true or false.
a) An is 124 cm tall, Binh is 1 m 24 cm tall. The two friends are of equal height.
b) This morning, Hung drank 750 ml of water, Cường drank over 1 liter of water. Hung drank less water than Cường.
c) A bag of green beans weighs 20 kg 500 g, a bag of rice weighs 25 kg. The bag of green beans is heavier than the bag of rice.

Solution Guide: Convert quantities to the same unit, compare, and answer the questions.

3. Solve Exercise 3 Page 57 Math Grade 3

Problem: Round the numbers to the nearest ten thousand.

Problem: Round the numbers to the nearest ten thousand.
a) Round the number 94,162 to the nearest ten thousand, resulting in the number .?.
b) Round the number 69,801 to the nearest ten thousand, resulting in the number .?.
c) Round the number 26,034 to the nearest ten thousand, resulting in the number .?.

Solution Guide:
- If the thousand digit is 1, 2, 3, or 4, keep the ten-thousand digit unchanged.
- If the thousand digit is 5, 6, 7, 8, or 9, add 1 to the ten-thousand digit.
- After rounding to the nearest ten thousand, all digits, including thousand, hundred, ten, and unit, become 0.

Answer:
a) Rounding 94,162 to the nearest ten thousand gives 90,000 (because the thousand digit is 4).
b) Rounding 69,801 to the nearest ten thousand gives 70,000 (because the thousand digit is 9).
c) Rounding 26,034 to the nearest ten thousand gives 30,000 (because the thousand digit is 6).

Challenge:

Solution Guide: Based on the method of breaking down numbers into the sum of ten-thousands, thousands, hundreds, tens, and units to fill in the missing numbers.

Answer:
a) 78,309 = 70,000 + 8,000 + 300 + 9
b) 18,300 = 10,000 + 8,000 + 300
c) 90,000 + 8,000 + 20 = 98,020
b) 40,000 + 5,000 + 60 = 45,060

This is a useful document for solving exercises on pages 56 and 57 of Math 3 Volume 2 textbook, the innovative book 'Horizon of Creativity.' Students can refer to it to solve exercises easily and improve their math skills.