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Solving Exercise 1 on Page 78 of Physics 10 Textbook
Exercise:
Characteristics of Sliding Friction
Solution:
+ Occurs at the contact surface of an object sliding on a surface.
+ Acts in the opposite direction of the velocity.
+ Proportional to the magnitude of the normal force, regardless of the contact area and velocity of the object.
Solving Exercise 2 on Page 78 of Physics 10 Textbook
Exercise:
What is the coefficient of sliding friction? What factors does it depend on? Write the formula for sliding friction force.
Solution:
We have: Fms = μt. N
Where μt is the coefficient of sliding friction, which depends on the materials and conditions of the contacting surfaces and is used to calculate the sliding friction force.
Solving Exercise 3 on Page 78 of Physics 10 Textbook
Problem:
State the characteristics of static friction.
Solution:
+ Appears at the contact surface of an object resting on a surface to keep the object stationary when subjected to a force parallel to the contact surface.
+ Has a maximum magnitude, and this maximum magnitude is greater than the sliding friction force.
Solution to Exercise 4 on Page 78 of Physics 10 Textbook
Problem:
Among the following ways of writing the formula for sliding friction force, which one is correct?
Solution:
Answer: D .
The correct formula for sliding friction force: Fmst = μtN
Solution to Exercise 5 on Page 78 of Physics 10 Textbook
Problem:
Is the book lying still on the horizontal table subjected to static friction force or not?
Solution:
The book on the horizontal table is not subjected to static friction force. In this case, the gravitational force is balanced by the reaction force of the table.
Exercise 6 Solution
Problem:
What happens to the coefficient of friction between two contact surfaces if the pressure between those surfaces increases?
A. Increases B. Decreases
C. Unchanged D. Cannot be determined.
Solution:
The answer is C.
The coefficient of friction depends only on the materials and conditions of the contact surfaces, so if the pressure between the surfaces increases, the coefficient of friction between those surfaces does not change.
Solving exercise 7 on page 79 of Physics 10 textbook
Exercise:
A pole vaulter uses a pole to give a ball an initial speed of 10m/s. The coefficient of sliding friction between the ball and the ice surface is 0.1. Taking g = 9.8m/s2. How far does the ball travel before stopping?
A. 39m B. 45m
C. 51m D. 57m.
Solution:
The answer is C.
Choose the positive direction as the direction of motion of the ball.
Solution for Exercise 8 on page 79 of Physics 10 textbook
Exercise:
A refrigerator weighing 890N moves uniformly on the floor. The coefficient of sliding friction between the refrigerator and the floor is 0.51. How much force is needed to push the refrigerator horizontally? Can the force found make the refrigerator move from rest?
Solution:
In Chapter I of Physics 10, students will delve into the Synthesis and Analysis of Forces - Equilibrium Conditions of Particles along with Exercise Solutions on page 58 of Physics 10.
