Solving exercises on pages 85 and 86 of Math 3 Volume 1 textbook, Sky Wings series

Buzz

Ngày cập nhật gần nhất: 15/4/2026

Content

Solving Math problems for 3rd grade on pages 85 and 86 of Sky Wings series, Volume 1.

Solving exercises on pages 85 and 86 of Math 3 Volume 1 textbook, Sky Wings series.

Solving problems with up to 2 calculation steps

1. Solve problem 1 on page 85 of Math 3 textbook

2. Solve problem 2 on page 85 of Math 3 textbook

3. Solve problem 3 on page 85 of Math 3 textbook

4. Solve exercise 4 on Page 85, 86 of Math textbook for Grade 3

5. Solve exercise 5 on Page 86 of Math textbook for Grade 3

6. Solve exercise 6 on Page 86 of Math textbook for Grade 3

Detailed solutions for exercises on pages 85 and 86 of Math 3 Volume 1 textbook, Sky Wings series. Providing step-by-step solutions for problems 1, 2, 3... in two-step calculation exercises. Students can refer to enhance their problem-solving skills and reinforce knowledge effectively.

Solving Math problems for 3rd grade on pages 85 and 86 of Sky Wings series, Volume 1.

Solving exercises on pages 85 and 86 of Math 3 Volume 1 textbook, Sky Wings series.

Solving problems with up to 2 calculation steps

1. Solve problem 1 on page 85 of Math 3 textbook

Problem: Tank 1 has 5 seahorses, Tank 2 has 3 more seahorses than Tank 1. How many seahorses are there in both tanks?

Solution Guide:
- Step 1: Find the number of seahorses in Tank 2 = Number of seahorses in Tank 1 + 3.
- Step 2: Total number of seahorses in both tanks = Number of seahorses in Tank 1 + Number of seahorses in Tank 2.

Answer:
The number of seahorses in Tank 2 is
5 + 3 = 8 (seahorses)
The total number of seahorses in both tanks is
5 + 8 = 13 (seahorses)
Answer: 13 seahorses.

2. Solve problem 2 on page 85 of Math 3 textbook

Problem: He collected 35 seashells, she collected 16 fewer seashells than him. How many seashells did the siblings collect together?

Solution Guide:
- Step 1: Number of seashells she collected = Number of seashells he collected - 16.
- Step 2: Total number of seashells the siblings collected = Number of seashells she collected + Number of seashells he collected.

Answer:
The number of seashells she collected is
35 - 16 = 19 (seashells)
The total number of seashells the siblings collected is
35 + 19 = 54 (seashells)
Answer: 54 seashells

3. Solve problem 3 on page 85 of Math 3 textbook

Problem: Bucket 1 contains 100 liters of sauce, Bucket 2 contains 18 liters less sauce than Bucket 1. How many liters of sauce do both buckets contain?

Solution Guide:
- Step 1: Find the number of liters of sauce in Bucket 2 = Number of liters of sauce in Bucket 1 - 18.
- Step 2: Find the total number of liters of sauce both buckets contain = Number of liters of sauce in Bucket 1 + Number of liters of sauce in Bucket 2.

Answer:
The second container holds liters of sauce
100 - 18 = 82 (liters)
Both containers hold liters of sauce in total
100 + 82 = 182 (liters)
The answer is: 182 liters

4. Solve exercise 4 on Page 85, 86 of Math textbook for Grade 3

Problem: a) A small car can carry 7 people, a large car can carry 5 times the number of people a small car can carry. How many people can both cars carry?
b) Thinh raises 9 ducks, the number of chickens is 6 times the number of ducks. How many chickens and ducks does Thinh raise in total?

Solution:
a) Step 1: Find the number of people the large car can carry = Number of people the small car can carry x 5.
Step 2: Find the total number of people both cars can carry = Number of people the small car can carry + Number of people the large car can carry.
b) Step 1: Find the number of chickens Thinh raises = Number of ducks x 6.
Step 2: Find the total number of chickens and ducks Thinh raises = Number of chickens + Number of ducks.

Answer:
a) The number of people the large car can carry is
7 x 5 = 35 (people)
The total number of people both cars can carry is
7 + 35 = 42 (people)
The answer is: 42 people
b) The number of chickens Thinh raises is
9 x 6 = 54 (chickens)
The total number of chickens and ducks Thinh raises is
9 + 54 = 63 (animals)
The answer is: 63 animals

In the next Math lesson, third-grade students will familiarize themselves with numerical expressions. To reinforce this lesson, don't forget to Solve exercises on Page 87, 88 of Math textbook for Grade 3, Wings of Kite. Detailed solutions for these exercises are provided in the following article for your reference and comparison with your own answers.

See more: Solve exercises on Page 87, 88 of Math textbook for Grade 3, Wings of Kite

5. Solve exercise 5 on Page 86 of Math textbook for Grade 3

Problem: Classes 3A and 3B participate in a tug of war game. Class 3A has 25 students, Class 3B has 23 students. The participating students are evenly divided into 4 teams. How many students are there in each team?

Solution:
- Step 1: Calculate the total number of students from both classes participating in tug of war.
- Step 2: Find the number of students in each team = Total number of students from both classes participating in tug of war : 4.

Answer:
The number of students from both classes 3A and 3B participating in tug of war is
25 + 23 = 48 (students)
Each team has the number of friends as
48 : 4 = 12 (friends)
The answer is: 12 friends

6. Solve exercise 6 on Page 86 of Math textbook for Grade 3

Problem: A train on the Hanoi - Lao Cai route, arriving at Yen Bai station, had 58 passengers disembark and 27 passengers board. The train continues to Lao Cai station, now with a total of 91 passengers on board. How many passengers were on the train before it stopped at Yen Bai station?

Solution:
- Step 1: Calculate the number of passengers reduced after stopping at Yen Bai station = Number of passengers disembarked - Number of passengers boarded.
- Step 2: Number of passengers before stopping at Yen Bai station = Remaining passengers on the train + Previously calculated number.

Answer:
After the train stops at Yen Bai station, the number of passengers reduced is:
58 - 27 = 31 (passengers)
Before the train stops at Yen Bai station, the number of passengers on the train is
91 + 31 = 122 (passengers)
The answer is: 122 passengers.

With the solution manual for exercises on Page 85, 86 of Math textbook for Grade 3, Wings of Kite provided here, it is hoped that students have grasped the knowledge, making exercises easy, and approaching similar problem types with confidence.

Frequently Asked Questions

What types of problems are covered in pages 85 and 86 of the Math 3 textbook?

Pages 85 and 86 of the Math 3 Volume 1 textbook cover a variety of two-step calculation problems. These exercises enhance students' problem-solving skills through practical scenarios, including addition and subtraction involving seahorses, seashells, and more.

How can I solve the seahorse problem from page 85 of the Math 3 textbook?

To solve the seahorse problem, first calculate the number of seahorses in Tank 2 by adding 3 to the 5 seahorses in Tank 1. Then, add both tank totals together for the final answer of 13 seahorses.

What is the solution to the tug of war problem on page 86?

To solve the tug of war problem, first find the total number of students from both classes, which is 48. Then divide that number by 4 teams, resulting in 12 students per team.

How do you calculate the total number of passengers before the train stopped at Yen Bai?

To find the total number of passengers before the train stopped at Yen Bai, add the number of passengers currently on the train (91) to the difference between those who disembarked (58) and those who boarded (27). This totals to 122 passengers.

What are the key benefits of solving exercises in the Math 3 textbook?

Solving exercises in the Math 3 textbook helps students reinforce their understanding of mathematical concepts. It enhances their problem-solving abilities, increases confidence, and prepares them for similar problem types they may encounter in future lessons.

Mytour's content is for customer care and travel encouragement only, and we are not responsible.

For errors or inappropriate content, please contact us at: [email protected]