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Mathematics exercises for Grade 3 on pages 48, 50, 51 of Workbook Volume 2.
Solving math exercises on pages 48, 50, 51 of Math 3 Workbook Volume 2, the book Connecting Knowledge with Life:
Dividing a four-digit number by a single-digit number
Activity 1
Solve Exercise 1 on Page 48 of Grade 3 Math Workbook
Instructions: Calculate.
Solution: Divide the digits of the dividend by the divisor from left to right.
Answer:
2. Solve Exercise 2 on Page 48 of Grade 3 Math Workbook
Problem: A factory produces 4,575 gears in 5 days. How many gears does the factory produce per day? It is known that the number of gears produced by the factory each day is the same.
Solution: The number of gears produced by the factory each day = Number of gears produced in 5 days : 5.
Answer:
The number of gears produced by the factory each day is:
4,575 : 5 = 915 (gears)
Final answer: 915 gears.
3. Solve Exercise 3 on Page 48 of Grade 3 Math Workbook
Problem: Number?
There are two duck farms. The first farm has 4,500 ducks, and the number of ducks on the second farm is equal to the number of ducks on the first farm decreased by 3 times.
a) The second farm has ? ducks.
b) Both farms have ? ducks.
Solution:
a) The number of ducks on the second farm = number of ducks on the first farm : 3.
b) Total number of ducks on both farms = number of ducks on the first farm + number of ducks on the second farm.
Answer:
a) The second farm has the number of ducks:
4,500 : 3 = 1,500 (ducks)
b) Total number of ducks on both farms is:
4,500 + 1,500 = 6,000 (ducks)
Final answer: a) 1,500 ducks.
b) 6,000 ducks.
Activity 2
1. Solve Exercise 1 on Page 50 of Grade 3 Math Workbook
Problem: a) Calculate.
b) Number?
Solution:
a) Perform division from left to right.
b) Based on the result in part a, fill in the blanks with appropriate numbers.
Answer:
1. Organize the troops, Commander!
2. Time for strategic deployment!
2. Solving Exercise 2 from Math Textbook Grade 3
Question: General Cao Lỗ commands an army of 6,308 soldiers. He wishes to divide them into smaller units, with each unit consisting of 7 soldiers. How many units can be formed, and how many soldiers will remain?
Guidelines: Divide the number of people in the army by the number of people in a group, then respond to the requirements of the question.
Answer:
We have: 6,308 ÷ 7 = 901 (remainder 1).
Therefore, 6,308 people can be divided into 901 groups with 1 person remaining.
3. Solving Exercise 3 from Math Textbook Grade 3
Question: a) A queen ant has a lifespan of 9,490 days, which is twice the lifespan of a worker ant. How many days is the lifespan of a worker ant?
b) Find the path for the nightingale to climb up the ground without encountering the bird.
Solution: The lifespan of the nightingale = the lifespan of the ant queen : 2.
Answer:
a)
The lifespan of the nightingale is:
9,490 : 2 = 4,745 (days)
Answer: 4,745 days.
b)
Practice
1. Solve Exercise 1 on Page 51 of Mathematics Grade 3 Textbook
Problem: Set up and solve the calculation.
Solution:
- Set up the division
- Perform division from left to right.
Answer:
2. Solve Exercise 2 on Page 51 of Mathematics Grade 3 Textbook
Problem: Mental calculation (following the example).
a) 7,000 : 7 b) 9,000 : 3 c) 8,000 : 4
Solution: Observe the example to mentally calculate division of round thousands.
Answer:
a) 7 thousand : 7 = 1 thousand
7,000 : 7 = 1,000.
b) 9 thousand : 3 = 3 thousand
9,000 : 3 = 3,000.
c) 8 thousand : 4 = 2 thousand
8,000 : 4 = 2,000.
3. Solve Exercise 3 on Page 51 of Mathematics Grade 3 Textbook
Solution Method: Mentally calculate the arithmetic operations, compare the results, and then fill in the appropriate signs in the blank spaces.
Answer:
4. Solve Exercise 4 on Page 51 of Mathematics Grade 3 Textbook
Problem: Number?
There are three satellites orbiting a celestial body. Satellite B orbits once at a distance of 1,527 km, which is three times the orbit of satellite A. So, satellite A orbits once at ? km.
Satellite C orbits once at a distance four times the orbit of satellite A. So, satellite C orbits once at ? km.
Solution:
+ Kilometers satellite A orbits once = Kilometers satellite B orbits once : 3.
+ Kilometers satellite C orbits once = Kilometers satellite A orbits once x 4.
Answer:
There are three satellites orbiting a celestial body. Satellite B orbits once at a distance of 1,527 km, which is three times the orbit of satellite A. So, satellite A orbits once at 509 km (because 1,527 km : 3 = 509 km).
Satellite C orbits once at a distance four times the orbit of satellite A. So, satellite C orbits once at 2,036 km (because 509 km x 4 = 2,036 km).
We hope that through the exercise solutions on pages 48, 50, 51 of Mathematics Grade 3 Textbook Volume 2, the book Connecting Knowledge with Life, students can easily do exercises and grasp the lesson on dividing four-digit numbers by one-digit numbers.
