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Solving math for Grade 4 on pages 13, 14 of Workbook 2 Practice Exercise 95 provides both solutions and guidance for exercises 1, 2, 3, 4 according to the curriculum. All are closely tailored to the learning content, making it easy for students to refer to and complete exercises in the workbook.
Solving math for Grade 4 on pages 13, 14 of Workbook 2 Practice Exercise 95
1. Solve problem 1 - Workbook of math exercises for grade 4 volume 2 page 13
Problem Statement:
Circle the letter preceding the correct answer:
Which shape has the largest area:
A. Shape (1)
B. Shapes (2)
C. Shapes (3)
Method of Solving
- Calculate the areas of the shapes and compare the results.
- Applying the following formulas:
+ Area of a square = side x side.
+ Area of a rectangle = length x width.
Answer
The area of shape 1 is: 5 x 5 = 25 (cm2)
The area of shape 2 is: 20cm2
The area of shape 3 is: 4 x 6 = 24 (cm2)
Thus, shape (1) has the largest area.
Choose A. Shape (1).
2. Solve Exercise 2 - Mathematics Workbook Grade 4 Volume 2 Page 13
Problem:
Fill in the blank (according to the example)
Perimeter: 20cm
Perimeter: ...
Perimeter: ...
Perimeter: ...
Solution Method
Let P be the perimeter of the parallelogram:
P = (a + b) x 2
where a, b are the lengths of the sides of the parallelogram measured in the same unit.
Answer
Let P be the perimeter of the parallelogram:
P = (a + b) x 2
where a, b are the lengths of the sides of the parallelogram measured in the same unit.
Perimeter of parallelogram (1) is:
P = (6 + 4) x 2 = 20 (cm)
Perimeter of parallelogram (2) is:
P = (5 + 3) x 2 = 16 (cm)
Perimeter of parallelogram (3) is:
P = (4 + 4) x 2 = 16 (cm)
Perimeter of parallelogram (4) is:
P = (5 + 4) x 2 = 18 (cm)
3. Solve Exercise 3 - Mathematics Workbook Grade 4 Volume 2 Page 14
Problem:
Fill in the blank (according to the example)
Parallelogram
Base: 4cm, height: 34cm, area: 136cm2
Base: 14cm, height: ..., area: 182cm2
Base: ..., height: 24cm, area: 360cm2
Solution Method
From the formula:
Area of parallelogram = length of base x height
it follows that:
+ Length of base (base) = area of parallelogram : height.
+ Height = area of parallelogram : length of base (base)
Answer
(2) Height: 13cm
(3) Length of base: 15cm
4. Solve Exercise 4 - Mathematics Workbook Grade 4 Volume 2 Page 14
Problem:
Given figure H formed by rectangle ABCD and parallelogram BEFC as shown in the diagram. Calculate the area of figure H?
Solution Method
- Area of figure H = area of rectangle ABCD + area of parallelogram BEFC.
+ Area of rectangle = length x width.
+ Area of parallelogram = length of base x height.
Answer
Since ABCD is a rectangle, AB = BC = 4cm.
The area of rectangle ABCD is:
4 x 3 = 12 (cm2)
The area of parallelogram BEFC is:
4 x 3 = 12 (cm2)
The area of figure (H) is:
12 + 12 = 24 (cm2)
Answer: 24cm2.
You are currently viewing the guide for solving math problems of Grade 4, pages 13 and 14, Workbook 2, Practice Exercise 95. You can review the guide for solving math problems of Grade 4, pages 12 and 13, Workbook 2, or preview the guide for solving math problems of Grade 4, page 15, Workbook 2, to better understand the lesson.
Wishing you all the best in learning mathematics.
