Solving Math for Grade 5 page 167, Practice Session

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Solving Math for Grade 5 page 167, Practice Session

Solving Math for Grade 5 page 167, Practice Session will help students quickly practice and enhance their knowledge effectively. If students are unsure how to solve the exercises, they can refer to the solving methods for each exercise provided below.

Solving Math for Grade 5 page 167, Practice Session

Exercise 1 - Solve Math 5 page 167
Problem:
A football field is drawn on a map with a scale of 1:1000 as a rectangle with a length of 11cm and a width of 9cm. Ask:
a) What is the perimeter of the football field in meters?
b) What is the area of the football field in square meters?

Solving Method:

- Actual length = length on the map × 1000.

- Actual width = width on the map × 1000.

- Convert actual length and width to meters.

- Perimeter = (length + width) × 2.

- Area = length × width.

Solution:
The length of the football field is: 11 x 1000 = 11000 (cm)
11000cm = 110m
The width of the football field is: 9 x 1000 = 9000 (cm)
9000cm = 90m
a) The perimeter of the football field is: (110 + 90) x 2 = 400 (m)
b) The area of the football field is: 110 x 90 = 9900 ( m²)
Answer: a) 400m ; b) 9900 m²
Exercise 2 - Solve Math for Grade 5 Practice page 167
Problem:
A square tile field has a perimeter of 48m. Calculate the area of that tile field.

Solving Method:

- Calculate side length = perimeter : 4

- Calculate area = side length × side length.

Solution:
The side length of the square tile field is:
48 : 4 = 12 (m)
The area of the square tile field is:
12 x 12 = 144 ( m²)
Answer: 144m².
Exercise 3 - Solve Math 5 Practice page 167
Problem:
A rectangular plot has a length of 100m, and its width is 3/5 of the length. Uncle Nam grows rice on that plot, and for every 100m², he gets 55kg of rice. How many kilograms of rice does Uncle Nam harvest on that plot?

Solving Guide

- Calculate width = length × 3/5.

- Calculate area = length × width.

- Find the ratio of the area to 100m².
- Calculate the amount of rice harvested = 55kg × ratio of area to 100m².

Solution:
The width of the rectangular plot is: 100 x 3/5 = 60 (m)
The area of the rectangular plot is: 100 x 60 = 6000 ( m²)
6000 m² is 100 times 100 m², so the ratio is: 6000 : 100 = 60 (times)

After the lesson on square meters, we continue practicing with this lesson, suggesting solving 5th-grade math problems page 28 29 will help students grasp the knowledge better.

Exercise 4 - Solve Math 5 page 167 Textbook
Problem:
A trapezoid has a large base of 12cm, a small base of 8cm, and an area equal to the area of a square with a side length of 10cm. Calculate the height of the trapezoid.

Solving Method:
- We need to calculate the area of the trapezoid (which is also the area of the square).
Area of square = side length × side length.
- From the formula for calculating the area of a trapezoid, we can calculate the height of the trapezoid by taking the area divided by the average of the two bases.

Solution:

The area of a trapezoid (also the area of a square) is: 10 x 10 = 100 (cm²).
The average of the two bases is: (12 + 8) : 2 = 10 (cm)
The height of the trapezoid is: 100 : 10 = 10 (cm)
Answer: 10cm.

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Here are the hints to Solve Math for Grade 5 page 167 in full detail. You prepare for the content of the Review on calculating area, volume of some shapes through section Solve Math for Grade 5 page 168 and the Practice exercises page 169 Mathematics Textbook Grade 5 through section Solve Math for Grade 5 page 169 to study Mathematics 5 better.

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