Solving Math Grade 5 pages 88, 89, Practice, Exercise 1, 2, 3, 4

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Ngày cập nhật gần nhất: 15/4/2026

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Guidance on Solving Math Grade 5 Pages 88, 89 (including solution methods)

1. Solve Exercise 1 - Math Grade 5 Pages 88, 89

2. Solve Exercise 2 - Solve Math Grade 5 Practice Pages 88, 89

3. Solve Exercise 3 - Solve Math Grade 5 Practice Pages 88, 89

4. Solve Exercise 4 - Solve Math Grade 5 Area of Triangle Practice Pages 88, 89

Guidance on Solving Math Grade 5 Pages 88, 89 (concise)

Students seeking solutions for exercises 1, 2, 3, 4 in Practice pages 88, 89 of Grade 5 Math textbook can refer to this document. They will find useful information to reinforce their knowledge.

Guidance on Solving Math Grade 5 Pages 88, 89 (including solution methods)

1. Solve Exercise 1 - Math Grade 5 Pages 88, 89

Problem:
Calculate the area of a triangle with a base length of a and a height of h:
a) a = 30.5 dm and h = 12dm
b) a = 16dm and h = 5.3 m.

Solution Method:
Students apply the formula: S = 1/2.a.h (where: a is the length of the base, h is the height), substitute numbers into the formula, carefully calculate to find the result.

2. Solve Exercise 2 - Solve Math Grade 5 Practice Pages 88, 89

Solution Method:
- Determine the base of the triangle: One of the 3 sides of the triangle
- Determine the altitude of the triangle: The altitude of the triangle is the length of the perpendicular from the vertex to the base.

Answer:

Right-angled triangle ABC:

- The base is AC and the corresponding height is BA.

- The base is AB and the corresponding height is CA.

Right triangle DEG:

- The base is DE and the corresponding height is GD.

- The base is DG and the corresponding height is ED.

3. Solve Exercise 3 - Solve Math Grade 5 Practice Pages 88, 89

Solution Method:

The area of a right triangle is equal to the product of the lengths of the two sides of the right angle divided by 2.

Answer:
Area of triangle ABC = (3 x 4) : 2 = 6 (cm²)
Area of triangle DEG = (3 x 5) : 2 = 7.5 (cm²).

4. Solve Exercise 4 - Solve Math Grade 5 Area of Triangle Practice Pages 88, 89

Solution Method:
Students observe the diagrams and determine the height, base of each triangle, then apply the formula to calculate the area of the triangle: S = (a x h) : 2 => Stated verbally: The area of the triangle equals the length of the base multiplied by the height, then divided by 2.

Answer:
a) AB = DC = 4cm, BC = AD = 3cm
The area of triangle ABC is:
AB x BC : 2 = (4 x 3) : 2 = 122 = 6 (cm²)
b) ME = 1cm, EN = 3cm, MQ = 3cm
The area of triangle MQE is:
3 x 1 : 2 = 1.5 (cm²)
The area of triangle NEP is:
3 x 3 : 2 = 4.5 (cm²)
The total area of triangles AQE and NEP is:
4.5 + 1.5 = 6 (cm²)
The area of triangle EQP is:
3 x 4 - 6 = 6 (cm²)
Or 3 x 4 : 2 = 6 (cm²)

Guidance on Solving Math Grade 5 Pages 88, 89 (concise)

Solve Exercise 1 Page 88 Math Grade 5 Textbook
Calculate the area of a triangle with a base length of a and a height of h:
a) a = 30.5 dm and h = 12dm
b) a = 16dm and h = 5.3 m.
Answer:

Attention: Referring to and practicing basic and advanced triangle problems for grade 5 will help students reinforce their knowledge and effectively tackle exercises.

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