Solving Math problems for 5th grade on page 110 of the textbook, Practice, solving exercises 1, 2, 3

Guide to solving Math problems for 5th grade on page 110, Practice (including solution methods)

1. Solve exercise 1 - Math 5 page 110, Practice

Problem:
Calculate the lateral and total surface area of a rectangular box with:
a) Length 25dm, width 1.5m, and height 18dm.
b) Length 4/5m, width 1/3m, and height 1/4m.

Solution method:
- Convert all quantities to the same length unit.
- Apply the following calculations:
+ The lateral surface area of the rectangular box is the perimeter of the base multiplied by the height.
+ The total surface area of the rectangular box is the lateral surface area plus the area of the two bases. 

2. Solve exercise 2 - Solve Math for 5th grade practice page 110

Problem:
An open rectangular box has a length of 1.5m, width of 0.6m, and height of 8dm. The exterior surface of the box is being painted. What is the painted surface area in square meters?

Solution method:
The area to be painted is the sum of the lateral and base area of the box.

Answer:
    8dm = 0.8m
The lateral surface area of the box is:
    (1.5 + 0.6) x 2 x 0.8 = 3.36 (m²)
The base area of the box is:
    1.5 x 0.6 = 0.9 (m²)
The painted area is:
    3.36 + 0.9 = 4.26 (m²)
              Answer: 4.26m²

3. Guide to solve exercise 3 page 110 Math 5 practice

Problem:

Correctly mark D, incorrect mark S.
a) The total surface area of the two rectangular boxes is equal.
b) The total surface area of the two rectangular boxes is not equal.
c) The lateral surface area of the two rectangular boxes is equal.
d) The lateral surface area of the two rectangular boxes is not equal.

Solution method:
- Apply the following calculations:
+ The lateral surface area of the rectangular box is the perimeter of the base multiplied by the height.
+ The total surface area of the rectangular box is the lateral surface area plus the area of the two bases.

Answer:

1. The left rectangular box has:
The lateral surface area is:
(1.5 + 1.2) x 2 x 2.5 = 13.5 (dm²)
The total surface area is:
13.5 + 2 x 1.5 x 1.2 = 17.1 (dm²)

2. The right rectangular box has:
The lateral surface area is:
(2.5 + 1.5) x 2 x 1.2 = 9.6 (dm²)
The total surface area is:
9.6 + 2 x 1.5 x 2.5 = 17.1 (dm²)

Therefore, the two rectangular boxes have equal total surface area, but unequal lateral surface area.

a) D;
b) S;
c) S;
d) D.

Guide to solving Math 5 page 110, Practice (concise)

Explore the intriguing world of 5th-grade Math with this challenging problem. Uncover the secrets in Exercise 1 - Math Class 5 practice page 110.

Dive into the realm of problem-solving with Exercise 2 - Math 5 practice page 110. Are you up for the challenge?

A rectangular open-topped box with dimensions 1.5m x 0.6m x 8dm undergoes a makeover. Calculate the painted surface area. Hint: 8dm = 0.8m. The painted area is: (1.5 + 0.6) x 2 x 0.8 = 3.36 m². The base area is: 1.5 x 0.6 = 0.9 m². Total painted area: 3.36 + 0.9 = 4.26 m². Answer: 4.26m².

In Chapter I, we acquaint ourselves with various measurement units, with a focus on Hectares. Check out tips on Math Class 5 pages 29, 30 to excel in 5th-grade Math.

In exercise 3 on page 110 of the Math 5 textbook

Correctly mark D for true and S for false.
a) The total area of two rectangular prisms is equal.
b) The total area of two rectangular prisms is not equal.
c) The lateral surface area of two rectangular prisms is equal.
d) The lateral surface area of two rectangular prisms is not equal.
a) D; b) S; c) S; d) D
Note: The rectangular prisms are given to have equal total areas but are placed in different positions, hence having equal total areas but different lateral surface areas.

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Above is the suggested solution for Math 5 page 110, Practice with complete details. Prepare for the content of the exercise on the lateral surface area and total area of cubes through the solution for Math 5 page 111 and the exercise on page 112 of Math 5 textbook through the solution for Math 5 page 112 to study Math 5 better.