If you wish to solve Math exercises for 5th grade, pages 137, 138, Concentrated practice, first, review time measurement concepts and read the beginning of the exercises. You can refer to the solving methods below for exercises 1, 2, 3, 4 to make solving the exercises easier.
Math exercises for 5th grade, pages 137, 138, Concentrated practice
Exercise 1 - Solve Math 5 page 137
Calculate
a) 17 hours 53 minutes + 4 hours 15 minutes;
b) 45 days 23 hours - 24 days 17 hours;
c) 6 hours 15 minutes x 6;
d) 21 minutes 15 seconds : 5.
Exercise 2 - Solve Math 5 concentrated practice page 137
Calculate:
a) (2 hours 30 minutes + 3 hours 15 minutes) x 3
2 hours 30 minutes + 3 hours 15 minutes x 3
b) (5 hours 20 minutes + 7 hours 40 minutes) : 2
5 hours 20 minutes + 7 hours 40 minutes : 2
Solving method:
Students perform calculations as with regular arithmetic operations according to the rules:
- For expressions involving addition and subtraction or multiplication and division, we perform them from left to right.
- For expressions containing both addition/subtraction and multiplication/division, perform multiplication/division first, then addition/subtraction.
- For expressions containing parentheses, perform operations inside the parentheses first, then those outside.
Answer:
a) (2 hours 30 minutes + 3 hours 15 minutes) x 3
= 5 hours 45 minutes x 3 = 15 hours 135 minutes = 17 hours 15 minutes.
= 2 hours 30 minutes + 3 hours 15 minutes x 3
= 2 hours 30 minutes + 9 hours 45 minutes = 11 hours 75 minutes = 12 hours 15 minutes.
b) (5 hours 20 minutes + 7 hours 40 minutes) : 2
= 12 hours 60 minutes : 2 = 6 hours 30 minutes.
5 hours 20 minutes + 7 hours 40 minutes : 2
= 5 hours 20 minutes + 6 hours 100 minutes : 2 = 5 hours 20 minutes + 3 hours 50 minutes
= 8 hours 70 minutes = 9 hours 10 minutes.
Exercise 3 - Solve Math 5 concentrated practice page 137
Problem Statement:
Circle the letter preceding the correct answer:
Huong and Hong arranged to meet at 10:40 a.m. Huong arrived at the meeting place at 10:20 a.m., while Hong arrived late by 15 minutes. How long did Huong have to wait for Hong?
A. 20 minutes; B. 35 minutes; C. 55 minutes; D. 1 hour 20 minutes.
Solution:
- Calculate the time Huong arrived early compared to the appointment time.
- The time Huong had to wait for Hong = the time Huong arrived early compared to the appointment time + the time Hong arrived late compared to the appointment time.
Answer:
The time Huong arrived early compared to the appointment time is:
10 hours 40 minutes – 10 hours 20 minutes = 20 (minutes)
The time Huong had to wait for Hong is:
Twenty minutes plus fifteen minutes equals thirty-five minutes.
The answer is thirty-five minutes.
So, the correct answer is option B.
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Above are suggestions for solving Math problems for 5th grade, pages 137 and 138, with detailed explanations. Prepare for the content on Velocity through section on solving Math problems for 5th grade, page 139, and exercises on pages 139 and 140 of Math textbook to enhance understanding of Math for 5th grade better.
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