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Explore Grade 7 math solutions on page 51 of Workbook 1 by Cánh Diều. This resource provides instructions and solutions for exercises 1, 2, 3... of Lesson 4: Rounding Numbers and Estimation. Watch to visualize the process and review learned concepts for a deeper understanding of the solving methods.
Additional Resources:
- Complete set of Grade 7 Math Solutions by Cánh Diều
- Grade 7 Math Solutions on page 36 of Workbook 1 by Kết Nối Tri Thức - Exercise 7: Set of Real Numbers
- Grade 7 Math Solutions on pages 49 and 50 of Workbook 1 by Chân Trời Sáng Tạo - Exercise 1: Rectangular Prism - Cube
Grade 7 math problem-solving on page 51 of Workbook 1 by Cánh Diều
Exercise 4: Rounding and Estimation
1. Solve Exercise 1 Page 51 Math Textbook Grade 7
Problem Statement: Round the number 98,176,244 to the nearest 5,000.
Solution Guide: Round the number to the nearest 5,000, meaning rounding to the tens of thousands place.
Answer:
Round the number to the nearest 5,000, which means rounding to the tens of thousands place. As the digit right next to the tens of thousands place is 6, greater than 5, add 1 to the tens of thousands place and replace the digits to the right with 0.
The number 98,176,244 rounded to the nearest 5,000 is 98,120,000.
2. Solve Exercise 2 Page 51 Math Textbook Grade 7
Problem: a) Round the number 4.76908 with precision 0.5.
b) Round the number -4.776908 with precision 0.05.
Solution Guide:
Round the number with precision 0.5, meaning rounding to the tenths place.
Round the numbers with precision 0.05, meaning rounding to the hundredths place.
Answer:
a) Round the number 4.76908 with precision 0.5 to get 4.8.
b) Round the number -4.776908 with precision 0.05 to get -4.78.
3. Solve Problem 3 Page 51 Math Textbook Grade 7
Solution Guide:
a) Use a handheld calculator for computation.
b) Round the number with precision 0.05, meaning rounding to the hundredths place.
Answer:
4. Solve Problem 4 Page 51 Math Textbook Grade 7
Problem: Apply the rounding rule to estimate the result of each calculation below:
a) (-28.29) + (-11.91); b) 43.91 - 4.49; c) 60.49 * (-19.51).
Solution: We will round the numbers to the tenths place and then perform the calculations.
Answer:
a) (-28.29) + (-11.91) ≈ (-28.3) + (-11.9) = -(28.3 + 11.9) = -40.2.
b) 43.91 - 4.49 ≈ 43.9 - 4.5 = 39.4.
Result:
5. Solve Exercise 5 Page 51 Math Textbook Grade 7
Problem: Scientists calculated the speed of light as 299,792,458 m/s. For simplicity, it is commonly rounded to 300,000,000 m/s. To which place value has the data been rounded?
Solution: Following the rule of rounding integers:
+ If the digit immediately to the right of the rounding place is less than 5, replace each digit to the right with 0.
+ If the digit immediately to the right of the rounding place is greater than or equal to 5, replace each digit to the right with 0 and add 1 to the rounding place digit.
+ If the digit immediately to the right of the rounding place is less than 5, replace each digit to the right with 0.
+ If the digit immediately to the right of the rounding place is greater than or equal to 5, replace each digit to the right with 0 and add 1 to the rounding place digit.
Rounding Integer Rule:
+ If the digit immediately to the right of the rounding place is less than 5, replace each digit to the right with 0.
+ If the digit immediately to the right of the rounding place is greater than or equal to 5, replace each digit to the right with 0 and add 1 to the rounding place digit.
Result:
Expect that with this Grade 7 math solving guide on page 51 of Workbook 1 by Cánh Diều, students can grasp the knowledge and understand the problem-solving approach for the lesson on Rounding Numbers and Estimation.
References:
- Solve Grade 7 math on page 54 of Workbook 1 by Cánh Diều - Exercise 5: Proportional Formula
- Solve Grade 7 math on page 58 of Workbook 1 by Cánh Diều - Exercise 6: Equal Ratio Sequence
